Proving a2 + b2 = c2 Using Odd Numbers

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Proving a2 + b2 = c2 Using Odd Numbers

a2 + b2 = c2    

(2n + 1) (2n + 1) + (2n2 + 2n) (2n2 + 2n) = (2n2 + 2n + 1) (2n2 + 2n + 1)

4n2 + 8n3 + 4n2 + 4n + 1 = 4n4 + 4n3 + 2n2 + 4n3 + 4n2 +2n + 2n2 +2n +1

       4n4 + 8n3 + 8n2 + 4n + 1 = 4n4 +8n3 + 8n2 +4n + 1

The above proves that a2 + b2 = c2 is correct using odd numbers and is a overall formula for Pythagorean triples.

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Perimeter   Odds

Perimeter = a + b + c

a= 2n + 1

b= 2n2 + 2n

c= 2n2 + 2n + 1

  = 4n2 + 6n + 2

Proving that this formula is correct:

If I take n=3

= 4x9 + 18 + 2

= 36 + 18 + 2

= 56

So if you look ...

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