So my prediction for the Third position will be that it is increased by 5, which will equal 38.
3+4+5+10+16 = 38
This shows that my prediction is correct once again.
From my previous work on the nth term I have made a rule for the T-Total. This rule is 5n.
I have made this rule to make it easier to use once I have found a rule to predict the T- Total using just the T-number and the size of the grid it is drawn on.
7 by 3 grid
I am now going to make a 7 by 3 grid to add results to my over all table which I am going to make.
The first T-shape (blue outline) T- Total is 1+2+3+9+16 = 31
The T- Number of this T-shape is 16
The second T-shape (red outline) T- Total is 2+3+4+10+17 = 36
The T- Number of this T-shape is 17
The third T-shape (brown outline) T- Total is 3+4+5+11+18 = 41
The T- Number of this T-shape is 18
I am now going to put my information in a table so I can look at more carefully.
I have not felt the need to make a prediction of what the brown T-shape’s T-Total was going to be because I have already explained that the T-Total will always increase by 5 when you move it to the right.
I am now going to look at the tables and the actually T-shapes to see if they have anything in common. I have also made tables to show the start of a rule I have made to predict the T- Total
5 by 3 grid
Using my 5n rule for the increase of the T- Total when you move it to the right, I am going to use it on the T- Number. And then using 7 multiply by the grid number and subtracting that answer from the 5n rule you should get the T- Total.
12 is the T- Number of the first position
5 * 12 = 60
7 * 5 = 35
If you subtract 35 from 60 you get 25 which is the T- Total of this T- Number
13 is the T- Number of the second position
5 * 13 = 65
7 * 5 = 35
If you subtract 35 from 65 you get 30 which is the T-Total of this T- Number
14 is the T- Number of the third position
5 * 14 = 70
7 * 5 = 35
If you subtract 35 from 70 you get 35 which is the T-Total of this T- Number
Here you can see that this rule works! I will prove that it works for the other grids that this rule works.
6 by 3 grid
16 is the T- Number of the third position
5 * 16 = 80
7 * 6 = 42
If you subtract 42 from 80 you get 37 which is the T-Total of this T- Number
Here my rule works again
7 by 3 grid
18is the T- Number of the third position
5 * 18 = 90
7 * 7 = 49
If you subtract 49 from 90 you get 41 which is the T-Total of this T- Number
Here you can see that this rule works for all of the grids.
I will now explain how it works.
Here is my T- Shape in blue. I have made this in algebraic expression in the next diagram.
T= the T- Number
G= the Grid size (number of columns)
T + (T-5) + (T-2G) + (T- 2G +1) + (T-2G -1) = 5T – 7G
Here you can see what my algebraic expression has showed. It has given me the rule to find the T-Total of any T-shape facing upward with just the knowledge of the T- Number and the size of the grid.
This works! You get the 5 multiplied by the T-Number by getting 5 numbers in the T- Shape. By applying the 5n rule to this you get 5T.
You get the 7G because of the structure of the T-shape.
For the row with the T-number in it the row equals 0
The next row up equals –1G because you have to subtract the grid size to get the T-Number
The last row from the T-Number is -2G because this is what you have to get the T-Number from this point.
When you add -1G and the three -2Gs you get -7G
I will prove that my rule works on a 10 by 10 grid.
5 * 65 – 7*10= 255
I will add up the numbers in the T- Total to prove that my rule is correct.
44+45+46+55+65= 225
My rule is correct!
First Extension
Moving the T-Shape 90 degrees to the right
Here I have moved my T-Shape 90 degrees to the right. I am going to investigate this T-Shape in the same why I did the last.
5 by 3 grid
My first position is in blue. The T- Number is 6. The T- Numbers will be in this place. This is the same as the last T-Shapes.
The first T-shape (blue outline) T- Total is 6+7+8+3+13 = 37
The T- Number of this T-shape is 6
The second T-shape (red outline) T- Total is 7+8+9+4+14 = 42
The T- Number of this T-shape is 7
The third T-shape (brown outline) T- Total is 8+9+10+5+15 = 47
The T- Number of this T-shape is 8
I am now going to make a table to put these results in a table to make it easier to read.
Here again I see that the T- Total is going up in 5. This is for the same reason as I stated before.
There is 5 numbers in each T-Shape so if you move the T-shape over each individual number is in creased by 1. Equaling 5 * 1
E.g. 6 changes to 7
7 changes to 8 etc
With the information that I poses from my last investigation I feel no need to write out the 6 by 3 grid and the 7 by 3 grid. I know what is going to happen.
So I am going find the rule for this T-Shape.
First I am going to write the algebraic expression of how to get all the numbers in the T-Shape from the T- Number.
This is my T-Shape.
T= T- Number
T+(T+1)+(T+2)+(T-3)+(T+7) = 5T+7
T= T- Number
By adding together the method of obtaining the numbers in the T- Shape from the T- Number I found the method for finding the T- Total by just using the number of columns in the grid and the T- Number!
I will show that my rule works using a 10 by 10 grid.
5 * 33 + 7= 172
I will now add the numbers in the T- Shape to see if I am correct.
33+34+35+45+25=172
This method is correct!
By first multiplying 5 by the T-total it is making 5 equal numbers.
Then by adding the 7 it is putting 2 extra into 3 and then 1 extra into one.
You get the 5 multiplied by the T- Number by 5 numbers being used in the T- Shape.
5 * 33 = 165
165 / 5 = 33
+1 +2 and then rearrange them to the original number in grid
This is how that method works.
Second Extension
Rotating the Original T- Shape 90 degrees to the left
Now I have rotated the T-shape 90 degrees to the left. I am going to try to find a method to predict the T –Total by just knowing the T- Number and the grid size (the number of columns in the grid)
I will now draw a 5 by 3 grid with the T-shape translated 3 times to collect information to find the rule.
The T- number is the same has it has been in last investigations. It will be 8 in the first position of this 5 by 3 grid.
5 by 3 grid
The first T-shape (blue outline) T- Total is 8+7+6+1+11 = 33
The T- Number of this T-shape is 8
The second T-shape (red outline) T- Total is 9+8+7+2+12 = 38
The T- Number of this T-shape is 9
The third T-shape (brown outline) T- Total is 10+9+8+3+13 = 43
The T- Number of this T-shape is 10
I am now going to put this information into a table so that it is easier to read.
This table shows the same information as the tables I have made before. It shows that the T- Total always goes up in fives.
I will have already explained this. But I will once again explain why.
There is 5 numbers in each T-Shape so if you move the T-shape over each individual number is in creased by 1. Equaling 5 * 1
E.g. 8 changes to 9
8 changes to 10 etc
I will not make any more tables of a 6 by 3 grid or a 7 by 3 grid because they show me the same information which I already know.
This is the T-Total will always go up in 5 if you move it to the right.
I am now going to try to find a method the same way I have done before.
I am going to break down the T- Shape in an algebraic expression to find the method.
Here is what it looks like as an algebraic expression
T = the T- Number
T+(T-1)+(T-2)+(T+3)+(T-7) = 5T-7
T = the T- Number
By adding together the method of obtaining the numbers in the T- Shape from the T- Number I found the method for finding the T- Total by just using the number of columns in the grid and the T- Number!
I will now prove that this rule works using a 10 by 10 grid.
5*89-7 =438
I will add up the numbers in the T- Shape to make sure my answer is correct.
87+88+89+77+97= 438
This rule works!
I will now explain why it works.
By first multiplying 5 by the T-total it is making 5 equal numbers. But these numbers are 7 higher then the T- Total.
5*97= 485
Then my subtracting 7 it equals the T-Total.
This rule is the opposite of the last extension piece because it is in the opposite direction to that T- Shape.
Third Extension
Rotating the original T-Shape 180 degrees
Here I have moved my T-Shape 180 degrees. I am going to investigate this T-Shape in the same why I did the last.
5 by 3 grid
My first position is in blue. The T- Number is 6. The T- Numbers will be in this place. This is the same as the last T-Shapes.
The first T-shape (blue outline) T- Total is 11+12+13+7+2 = 45
The T- Number of this T-shape is 2
The second T-shape (red outline) T- Total is 12+13+14+8+3 = 50
The T- Number of this T-shape is 3
The third T-shape (brown outline) T- Total is 13+14+15+9+4 = 55
The T- Number of this T-shape is 4
I am now going to put this information into a table so that it is easier to read.
This table shows the same information as the tables I have made before. It shows that the T- Total always goes up in fives.
I will have already explained this. But I will once again explain why.
There is 5 numbers in each T-Shape so if you move the T-shape over each individual number is in creased by 1. Equaling 5 * 1
E.g. 11 changes to 12
12 changes to 13 etc
I will not make any more tables of a 6 by 3 grid or a 7 by 3 grid because they show me the same information which I already know.
This is the T-Total will always go up in 5 if you move it to the right.
I am now going to try to find a method the same way I have done before.
I am going to break down the T- Shape in an algebraic expression to find the method.
Here is what it looks like as an algebraic expression
T = the T- Number
T+(T+G)+(T+2G)+(T+2G-1)+(T+2G+1) = 5T+7G
T = the T- Number
By adding together the method of obtaining the numbers in the T- Shape from the T- Number I found the method for finding the T- Total by just using the number of columns in the grid and the T- Number!
I will now prove that this rule works using a 10 by 10 grid.
5*25+7*10= 195
I will add up the numbers in the T- Shape to make sure my answer is correct.
25+35+45+44+46= 195
This rule is correct.
This is how it works.
You get the 5 multiplied by the T-Number by getting 5 numbers in the T- Shape. By applying the 5n rule to this you get 5T.
For the row with the T-number in it the row equals 0
The next row up equals +1G because you have to subtract the grid size to get the T-Number
The last row from the T-Number is +2G because this is what you have to get the T-Number from this point.
When you add +1G and the three +2Gs you get +7G
This rule is the opposite of the first investigation because it is in the opposite direction to the original T- Shape.