• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month
Page
1. 1
1
2. 2
2
3. 3
3
4. 4
4
• Level: GCSE
• Subject: Maths
• Word count: 1306

# T-Total. In order to find the relationship between the T-number and the T-total I need to show the numbers in the T algebraically

Extracts from this document...

Introduction

James Benson 11sb

T-Total

 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 77 78 79 80 81 82

Highlighted in yellow are 5 numbers in a shape of a T. If I add these five numbers I get the T-total, e.g. 1+2+3+11+20=37

Highlighted in yellow and coloured redis what is called the T-number.

Middle

N-19

N-18

N-17

N-9

N

This is worked out with the grid size because how you get one square up is by taking 9 because it is a 9*9 grid. If I move left I +1 and if you move right you -1. If I add all the numbers together in the diagram above you get 63 and that is the same wherever the T is on a 9*9 grid.

 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 77 78 79 80 81 82

T-total= 37

+5

T-total=42

+5

T-total=47

Every time the T moves right the T-total is +5 so this means all the t-totals have a relationship with the 5* table.

So if I * the T-number by 5 I get 100 and then if we go back to diagram that showed T algebraically and use 63 that I worked out from it. Then if I -63 from 100 I get 37 and that is the t-number.

So if I put that in a formula it looks something like this N=T+63

5

The relationship between the T-number, T-total and the grid size

The examples I used in the first section only worked for a 9*9 size grid and to find so to find the relationship between the grid size I have to try the same thing with different grid sizes and then notice a pattern.

 N-19 N-18 N-17 N-9 N

This is the T is written algebraically for a 9*9 size grid add all the numbers in the T up I get 63

 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24

1st 3 rows of a 8*8 grid

 N-17 N-16 N-15 N-8 N

Conclusion

That is only to work out how to get from the first N(N1) to the second N(N2) what I need to find out is how to get from the N1 to the second T-total(T2). So if we put the translation into a formula to find T2 from N1 this is what it looks like. T2=5[(n+x)+(wY)]-(7w)

Replacing the letters for numbers in the example I should be able to work it out like this T2=5[(20+4)+(3*9)]-(7*9)

=5[24+27]-63

=5[51]-63

=255-63

=192

so now to find out if my formula is correct I will work out T2 by adding the numbers in the T, 32+33+34+42+51=192

That concludes my maths coursework…

Maths coursework

This student written piece of work is one of many that can be found in our GCSE T-Total section.

## Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Related GCSE T-Total essays

1. ## T-Total Maths

+ 7 = 55+7 = 62 As expected, the equation has produced yet another correct answer. Another example is below, N= 12 T= (5x 12) + 7 = 60+7 = 67 Here is the last equation I will show from the 9 by 9 grid to show that the equation N=13 T= (5x13)

2. ## T Total and T Number Coursework

I will use 'g' to represent the grid size from now on. The final formula for the T-total on any grid size is therefore 5n-7g So, for a 9x9 Grid size the formula would be: 5n- where n is the t-number.

1. ## T-Shapes Coursework

See overleaf. This table shows all the Sums of the Tails, with the Middle Number 15 and the Grid Width 10: Tail Length (l) 1 2 3 4 5 Tail Boxes { +25 25 25 25 25 +35 35 35 35 +45 45 45 +55 55 +65 Sum of Tail

2. ## T-Shapes Coursework

- 7(8) = 235 - 56 = 179 T-total = 30 + 31 + 32 + 39 + 47 = 179 Any T-Total of a T-Shape can be found if you have the 2 variables of a T-Number and a grid size for T shapes that extends upwards, using the formula Tt = 5n - 7g.

1. ## T totals. In this investigation I aim to find out relationships between grid sizes ...

T=(205-18)+15 T=187-15 T=172 Using our equation found in the preliminary work we can work out the real value of the translated shape, (it has a v number of 38); T=(5x38)-(2x9) T=190-18 T=172 Thus proving our theory right that the equation can be used for any type of translation, vertical, horizontal or a combination of the both.

2. ## T-Total Maths coursework

Formula: T=5N-7 I tested that when: T-number= 42 T-total= 204 Below is a T-shape, and in each cell how number is connected with T-number on a 7 by 7 number grid. To prove the formula: T= N+N+1+N+9+N+2+N-5 T= 5N-7 How the formula works there are some example shown in below

1. ## From the table I have noticed that when that when you move a T ...

From my this experiment I can identify that 5t- t- numbers added together will always give you the T total. 8 Grid t-17 t-16 t-15 t-8 T T total= (t) + (t-8) + (t-16) + (t-15) + (t-17) =5t-56 1 2 3 10 18 T total=1+2+3+10+18=34 18x5=90-56=34 I am now

2. ## T- total T -number coursework

We then times the 54 by 5 because it rises 5 ever time the t- number goes up. Then we + the t-total from the original t-shape and I come out with the t-total for the green t-shape. This is another way to work out the t-total.

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to