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• Level: GCSE
• Subject: Maths
• Word count: 2712

# T-Totals (A*) Firstly I have chosen to look at the 9 by 9 grid. I will be taking five t-numbers in a row and investigating the t-totals for them. Once I have completed all five, I will then look for a formula to link those five

Extracts from this document...

Introduction

T-totals

Introduction:

During this investigation I will be looking at different sized number grids, for example: (9 by 9, 10 by 10, etc…..). By looking at these different grids I will be drawing shapes on them called the t-shape. When I have drawn these, I will then be adding up the five numbers inside the t-shape. The sum of these five numbers will be called the t-total. Once I have found the t-total I will then record the number at the base of the t-shape which will be called the t-number. After recording all these figures I will then try and find whether there is a relationship between the t-number and the t-total thus coming up with a formula that links them.

Grid 1: (9 by 9)

Firstly I have chosen to look at the 9 by 9 grid. I will be taking five t-numbers in a row and investigating the t-totals for them. Once I have completed all five, I will then look for a formula to link those five and then I will be moving onto the second grid.

Number 1:

 11 12 13 21 30

The t-number in this case will be 30.

The t-total is 30+21+13+12+11 which will give us 87.

T-number: 30

T-total: 87

Number 2:

 12 13 14 22 31

The t-number in this case will be 31.

The t-total is 31+22+12+13+14 which will

give us 92.

T-number: 31

T-total: 92

 13 14 15 23 32

Number 3:

Middle

48

The t-number in this case will be 48.

The t-total is 48+38+28+27+29 which will

give us 170.

T-number: 48

T-total: 170

Formula:

After investigating the t-numbers from 44 to 48 and comparing them with their t-totals, I have noticed that every time I increase the t-number by one the t-total goes up by five. I found this out by doing the table seen below:

 Nth term 1 2 3 4 5 T-number 44 45 46 47 48 T-total 150 155 160 165 170 Difference +5 +5 +5 +5

This table shows us that 5 multiplied by the nth term added to 145 will give us the t-total.

Overall formula:

I have also figured out a formula that will give us the t-total of any chosen t-number at random on a 10 by 10 grid. I did this by calling the t-number the nth term in each case and working out a formula from there, what I have done can be seen looking at the table below:

 T-number* 44 45 46 47 48 T-total 150 155 160 165 170 Difference +5 +5 +5 +5

*nth term

Formula: 5n-70.

Checking:

I will now be checking if the formula I have come up with was correct, I will do this by choosing a random number on the 10 by 10 grid and substituting the t-number into the equation and coming up with the t-total without adding up the rest of the numbers. I will then add up the t-total and if it matches my prediction my formula will be correct.

The random number I have chosen is 72; this will be the t-number for checking my formula. I am now going to substitute the number into the equation:

T-total = 5(72)-70

T-total = 290

Now that I have got my prediction I will do what I have done for all the other numbers and find it out manually.

Predicted number:

 51 52 53 62 72

The t-number in this case will be 72.

The t-total is 72+62+52+51+53 which will

give us 290.

T-number: 72

T-total: 290

My formula has turned out to be correct, I will keep this information and move on to the third grid.

Grid 3: (11 by 11)

Thirdly I have chosen to look at the 11 by 11 grid. I will be taking five t-numbers in a row and investigating the t-totals for them. Once I have completed all five, I will then look for a formula to link those five and then I will be moving onto the final grid.

Number 1:

 60 61 62 72 83

The t-number in this case will be 83.

The t-total is 83+72+61+62+60 which will give us 338.

T-number: 83

T-total: 338

Number 2:

 61 62 63 73 84

The t-number in this case will be 84.

The t-total is 84+73+62+63+61 which will

give us 343.

T-number: 84

T-total: 343

 62 63 64 74 85

Number 3:

The t-number in this case will be 85.

The t-total is 85+74+63+64+62 which will

give us 348.

T-number: 85

T-total: 348

Number 4:

 63 64 65 75 86

The t-number in this case will be 86.

The t-total is 86+75+64+65+63 which will

give us 353.

T-number: 86

T-total: 353

Number 5:

 64 65 66 76 87

The t-number in this case will be 87.

The t-total is 87+76+65+66+64 which will

give us 358.

T-number: 87

T-total: 358

Formula:

After investigating the t-numbers from 83 to 87 and comparing them with their t-totals, I have noticed that every time I increase the t-number by one the t-total goes up by five. I found this out by doing the table seen below:

 Nth term 1 2 3 4 5 T-number 83 84 85 86 87 T-total 338 343 348 353 358 Difference +5 +5 +5 +5

This table shows us that 5 multiplied by the nth term added to 333 will give us the t-total.

Overall formula:

I have also figured out a formula that will give us the t-total of any chosen t-number at random on a 11 by 11 grid. I did this by calling the t-number the nth term in each case and working out a formula from there, what I have done can be seen looking at the table below:

 T-number* 83 84 85 86 87 T-total 338 343 348 353 358 Difference +5 +5 +5 +5

Conclusion

I also noticed that the number taken away from 5n is the same as seven multiplied by the grid number every time, so 9 would be 63, 15 would be 105 and so on.

By figuring this out I managed to make a formula linking the t-number of any grid to its t-total using a quick simple formula. The formula is as follows:

T-total = 5n-7g

N=the t-number

G= the grid number

Now I will simply try the formula out on a random t-number chosen on a random grid and see if my formula works out correctly.

The random t-number I have chosen is 109 from the grid 11 by 11. I am now going to substitute these figures into the equations I have got and predict the t-total without adding the numbers. I will then check my prediction and if it matches the answer I add up I will know that my formula is correct.

Prediction:

T-total = 5n-7g          (n=109 , g=11)

(5*109) - (7*11            545-77

My prediction is that the t-total for t-number 109 is going to be 468. I will now check to see if my answer is correct.

Check formula:

 86 87 88 98 109

The t-number in this case will be 109.

The t-total is 109+98+87+86+88 which will

give us 468.

T-number: 109

T-total: 468

My formula is correct; I have solved the relationship between t-numbers and t-totals on any sized grid. The formula (5n-7g) is the answer to this problem.

This student written piece of work is one of many that can be found in our GCSE T-Total section.

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