10p10p10p10p10p 20p20p10p
20p10p10p10p 20p10p20p
10p20p10p10p 10p20p20p
10p10p20p10p an easy way to do it is to
10p10p10p20p it is to put 20p up every go.
The sequence goes up in a regular pattern this formula shows this pattern and makes it easier to predict the next value. To get the next value you simply get the last two terms and add them together to get the nth term. I will now take my last two terms and add them together. So I would add T4+T5 together.
Therefore pg3
5+8=13
13=T6 To see if I’m right ive done a list for
60p to see if my formula works and according to the pattern there should be 13 ways for 60p.
60p
10p10p10p10p10p10p
10p20p10p10p10p
20p10p10p10p10p t10p10p20p10p10p
10p10p10p20p10p
10p10p10p10p20p
10p10p20p20p
10p20p10p20p
20p10p10p20p
20p10p20p10p
20p20p10p10p
10p20p20p10p
20p20p20p
My prediction is correct 13 ways for 60p by using
The formula.
Table of results pg4
Amount No. of ways
10p 1
20p 2
30p 3
40p 5
50p 8
60p 13
That’s my table of results
Investigation 2 pg5
This is an investigation to show the different combinations of putting in a 10p and 50p into a pay phone and seeing if there is any pattern that forms from the results. From this pattern I will try and find a formula. In this investigation I have started the call cost from 40p as I assume that if I started with a 10p, the first three results would all be the same, as 50p would be redundant in any call less than 50p therefore the data that I have found out for the first three results would be useless and the formula would be incorrect.
40p
10p10p10p10p
There is 1 combination for 40p
50p
10p10p10p10p10p
50p
There are 2 combinations for 50p.
60p pg6
50p10p
10p50p
10p10p10p10p10p10p
There are 3 combinations for 60p.
70p
10p10p10p10p10p10p10p
50p10p10p
10p50p10p
10p10p50p
There are 4 combinations for 70p
80p
50p10p10p10p
10p50p10p10p
10p10p50p10p
10p10p10p50p
10p10p10p10p10p10p10p10p
There are 5 combinations for 80p
90p pg7
10p10p10p10p10p10p10p10p10p
10p10p10p10p50p
10p10p10p50p10p
10p10p50p10p10p
10p50p10p10p10p
50p10p10p10p10p
There are 6 combinations for 90p
1.00£
50p50p
10p10p10p10p10p10p10p10p10p10p
50p10p10p10p10p10p
10p50p10p10p10p10p
10p10p50p10p10p10p
10p10p10p50p10p10p
10p10p10p10p50p10p
10p10p10p10p10p50p
There are 8 combinations for 1.00£
1.10£ pg8
50p50p10p10p
50p10p50p
10p50p50p
10p10p10p10p10p10p10p10p10p10p10p
10p10p10p10p10p10p50p
10p10p10p10p10p50p10p
10p10p10p10p50p10p10p
10p10p10p50p10p10p10p
10p10p50p10p10p10p10p
10p50p10p10p10p10p10p
50p10p10p10p10p10p10p
There are 11 combinations for 1.10£
1.20£
10p10p10p10p10p10p10p10p10p10p10p10p
50p50p10p10p
50p10p50p10p
50p10p10p50p
10p50p10p50p
10p10p50p50p
10p50p50p10p
10p10p10p10p10p10p10p50p
10p10p10p10p10p10p50p10p
10p10p10p10p10p50p10p10p
10p10p10p10p50p10p10p10p
10p10p10p50p10p10p10p10p
10p10p50p10p10p10p10p10p
10p50p10p10p10p10p10p10p pg9
50p10p10p10p10p10p10p10p
There are 15 combinations for 1.20£
Results tables 10p+50p
Amount No. of ways
40p 1
50p 2
60p 3
70p 4
80p 5
90p 6
1.00 8
1.10 11
- 15
1.30 20
Formula = Tn =Tn –1 + Tn –5 pg10
From this formula I can predict that the next number in the sequence for 1.30 should be 20.i can predict this because Tn-1= 15 and Tn-5 = 5 so 15 +5 = 20. To prove this, here are all the listings for 1.30
10p10p10p10p10p10p10p10p10p10p10p10p
10p
10p10p10p10p10p10p10p10p50p
10p10p10p10p10p10p10p50p10p
10p10p10p10p10p10p50p10p10p
10p10p10p10p10p50p10p10p10p
10p10p10p10p50p10p10p10p10p
10p10p10p50p10p10p10p10p10p
10p10p50p10p10p10p10p10p10p
10p50p10p10p10p10p10p10p10p
50p10p10p10p10p10p10p10p10p
50p10p10p10p50p
10p50p10p10p50p 10p50p10p50p10p
10p10p50p10p50p 10p50p10p10p50p
10p10p10p50p50p 50p50p10p10p10p
10p10p50p50p10p 50p10p50p10p10p
10p50p50p10p10p
There are 20 sequences that prove that my formula is correct.
General Investigation
Pg11
I have found that my formula relate to the coin used.
Tn = Tn –1 + Tn -5
-1 = 10p used
-5 = 50p used
So for any formula using coins you could use the formula.
Tn = Tn – x + Tn –y
X and y being the coins used in the formula.
This is also true of the first formula using 10p and 20p coins.
The theory will only work if both the coin values used a 10p coin and a 1.00£ in the formula.
Tn = Tn –1 + Tn –10
Would not work cause it has to be a prime number to work as with x and y formula, unless both x and y are prime numbers it will not work.
pg12
I have found out the formulas for the pay phone problem and I have investigated further and found out that prime numbers are very important in the pay phone problem
By Danny James Dawson