The coursework problem set to us is to find the shape of a gutter that generates the maximum flow of water and that can contain the most water in it. The plastic used for the gutter can be no more than 30cm in width.

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Maths Coursework

Investigation

        The coursework problem set to us is to find the shape of a gutter that generates the maximum flow of water and that can contain the most water in it. The plastic used for the gutter can be no more than 30cm in width.

Plan

       To find the gutter that produces the biggest flow of water I must investigate different shapes of gutters to find which generates the largest volume. To do this I will use a variety of different shapes. I will firstly investigate a rectangle shaped gutter changing the length of the sides to form the largest volume. This is the simplest shape with a small amount of sides. The second I will investigate will be an isosceles triangle shaped gutter. The third shape I will investigate will be a trapezium shaped gutter and lastly I will investigate a semicircular shaped gutter. In calculating the trapezium and the triangle I will be using angles and length. This will take many trigonometry calculations. So rather than using a pen and paper methods to calculate these I will use spreadsheets typing in formulas to calculates answers which will only involve myself typing in the values of the shape.

Spread sheets for shapes that change in angle

Side : In this box the length of the side of the shape is put.

Angle : Into this box the angle that the side forms with the perpendicular height is put.

Height : The angle and the side are now used to find the height. This can only be done using trigonometry. By putting this formula in :

(A2*cos(Pi()/ 180*B2))

Top : Using trigonometry again this length can be found, by using the same formula but changing the role.

Area : The area of the shape can be worked out. Again by using a formula : multiplying cell names( eg: B2 ) of the previously worked out sides

Triangular shaped gutters

          An isosceles triangular base gutter has fewer variations than the other shapes that I will investigate. This is because the shape is symmetrical and has only 2 sides meaning that there is no possible variation in length only in the angle at which they are positioned. The width of the plastic used is 30cm, because both sides must be the same lengths they are 15cm each. The angles should be varied by each side moving down or up 10° from the centre of the triangle for 90°.  

                                       b

                               15cm           h          15cm

          Using sine the length of ‘b’ can be worked out and using cosine ‘h’ can be worked out, by the multiplication of the 2 we can get the area of the entire triangle.

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When calculating the results I will not workout every area of the triangle by changing the angles by 1° at a time, as this would take much unnecessary time. Instead I will start with working out the area for every 10°. Then my results should show me the 2 points where the highest area is and then I can do every 1° between these 2 points and find the maximum area.

 

          As I said above the 2 points that ...

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