• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month
Page
  1. 1
    1
  2. 2
    2
  3. 3
    3
  4. 4
    4
  5. 5
    5
  6. 6
    6
  7. 7
    7
  8. 8
    8
  9. 9
    9
  10. 10
    10
  11. 11
    11
  12. 12
    12
  13. 13
    13
  • Level: GCSE
  • Subject: Maths
  • Word count: 1839

The Fencing Problem.

Extracts from this document...

Introduction

The Problem A farmer has exactly 1000 metres of fencing and wants to fence off a plot of level land. She is concerned about the shape of the plot, but must have a perimeter of 1000m. So it could be 400m 50m 450m 1000m Or anything else with a perimeter (or circumference) of 100m. She wishes to fence of the plot, which contains the maximum area. Investigate the shape, or shapes that could be used to fence in the maximum area using exactly 1000 metres of fencing each time. I am going to investigate different with shapes with the perimeter of 1000 m to find out the maximum area. I will start with rectangles as they have drawn some rectangles already. Then I will try Isosceles triangle and equilateral triangle. Then I will do some regular polygons. The I will try a circle. Rectangle and Square Length Width Area 0 500 0 10 490 4900 20 480 9600 30 470 14100 40 460 18400 50 450 22500 60 440 26400 70 430 30100 80 420 33600 90 410 36900 100 400 40000 110 390 42900 120 380 45600 130 370 48100 140 360 50400 150 350 52500 160 340 54400 170 330 56100 180 320 57600 190 310 58900 200 300 60000 210 290 60900 220 280 61600 230 270 62100 240 260 62400 ...read more.

Middle

310 190 60000 244.949 46540.31 1000 390 305 195 55000 234.5208 45731.55 1000 400 300 200 50000 223.6068 44721.36 1000 410 295 205 45000 212.132 43487.07 1000 420 290 210 40000 200 42000 1000 430 285 215 35000 187.0829 40222.82 1000 440 280 220 30000 173.2051 38105.12 1000 450 275 225 25000 158.1139 35575.62 1000 460 270 230 20000 141.4214 32526.91 1000 470 265 235 15000 122.4745 28781.5 1000 480 260 240 10000 100 24000 1000 490 255 245 5000 70.71068 17324.12 1000 500 250 250 0 0 0 1000 The formula for a triangle is 1/2 x base x height The formula used for column 3 which is a is =A4/2 Each time the coordinate changes. The formula used for column 4 is =POWER(B4,2)-POWER(C4,2) Each time the coordinate changes. We need to do this in order to work out the height. The formula for column 5 which is height is =POWER(D4,0.5) We need to work the height out in order to work out the area. The formula for column 6 which is area is =(A4*E4)/2 I then used my i.c.t skills to plot a graph between the relationship between base and height in order to help me find the maximum area within an isosceles triangle. ...read more.

Conclusion

I have used my i.c.t skills to plot a graph to find the relationship between the number of sides in a polygon and the area. I noticed from my graph Decagon has the largest area as it has most sides. My predication was right as the number of side's increases so does the area. I also noticed from triangle, rectangle, square, pentagon, heptagon, octagon, nonagon and decagon the area is increasing and the shape is becoming more like a circle therefore I decided to try circle next. Circle The formula for the area of a circle is ?rxr We need to find r We know circumference = 2?r Circumference = Perimeter We know the perimeter is = to 1000 Therefore 1000 = 2?r To find out r you do r = 1000/2? R= 159.1549431 Now we can work out the area. Area = ?rxr Area = ? x 159.159.1549431 x 159.1549.431 Area = 79577.47155m The largest possible area for a circle is 79577.47144m squared . Conclusion I conclude that the area that which gave the farmer the most area is a circle. This is because it is a regular shape that has infinite number of sides, the maximum area that the farmer could get would be 79577.47155m squared. I also found out as the number of sides increases so does the area. Regular shapes give the largest area. ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our GCSE Fencing Problem section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related GCSE Fencing Problem essays

  1. The Fencing Problem

    Area = ((250 + 150)( 2) ( 86.602 = 4,330.127m� The total area of the hexagon is the trapezium area plus the rectangle area. 4,330.127 + 50,000 = 54,330.127m� I will now input my information into a table showing the area of a hexagon and its relation to the side lengths.

  2. The Fencing Problem

    indicated the symmetry with a line through the highest point on the graph. Base [a] (m) Side [b] (m) Angle (�) Height [h] (m) Perimeter (m) Area (m�) 100 400 80 393.92 1000 39392.31 100 400 82 396.11 1000 39610.72 100 400 84 397.81 1000 39780.88 100 400 86 399.03

  1. t shape t toal

    1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 Centre of Rotation Rotation (degrees)

  2. My investigation is about a farmer who has exactly 1000 metres of fencing and ...

    I now want to try a heptagon, 7-sides, to see if this makes a difference to my results. Before I do that though, I want to find a formula which will give me the area of a regular polygon. I want to do this because when I looked back at

  1. Fencing Problem

    * I will multiply the base x height to give me the area of the two triangles. The reason I am not using 1/2 base x height is because that will find me the answer of one of the triangles, i.e.

  2. A farmer has exactly 1000m of fencing and wants to fence off a plot ...

    0 200 310 490 1000 500 190 10 300 16881.94302 200 320 480 1000 500 180 20 300 23237.90008 200 330 470 1000 500 170 30 300 27658.63337 200 340 460 1000 500 160 40 300 30983.86677 200 350 450 1000 500 150 50 300 33541.01966 200 360 440 1000

  1. Regeneration has had a positive impact on the Sutton Harbour area - its environment, ...

    In contrast to this, Commercial Road scored quite low in the survey. There are a couple of reasons for this. The major one is that at the time of the survey, many of the houses had scaffolding outside them amongst builders' rubble.

  2. Fencing problem.

    The figure 's' shall be found by the following formula: Area of a scalene triangle (s) = the total perimeter of the scalene triangle � 2 I shall now discover the area of the triangle below: Area of a scalene triangle (s)

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work