The Fencing problem.

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The Fencing problem

I am making an investigation to find out how shape affects area. In my investigation I am going to see how area is affected when I change the shapes of different shapes all with the perimeter of 1000m. I am going to experiment with different side lengths and different numbers of sides. I will record my results in graphs and tables and come to a conclusion.

Hypothesis

My hypothesis is that as the number of sides rises, so will the areas.  

Results

Here are my results for 4-sided shapes.

A rectangle, with the width of 25m and the length of 475m.

Area = 25m x 475m

Area = 11875m

A rectangle with the length of 50m and the width of 450m

Area = 50m x 450m

Area = 22500m

A rectangle with the length of 425m and the width of 75m

Area = 75m x 425m

Area = 31875m

The fencing problem

By Siân Salkeld

A rectangle with the length of 400m and the width of 100m.

Area = 400m x 100m

Area = 40000

 

A rectangle with the length of 375m and the width 125m

Area = 125m x 375m

Area = 46875m

A rectangle with the length of 350m and the width of 150m

Area = 350m x 150m

Area = 52500m

A rectangle with the length of 325m and the width of 175m

Area = 325 x 175

Area = 56875

A rectangle with the length of 300m and the width of 200m

Area = 300m x 200m

Area = 60000m

 A rectangle with the length of 275m and the width of 225m

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Area = 275m x 225m

Area = 61875

A square with four sides of 250m

Area = 250m x 250m

Area = 62500

After increasing the width by 25m and decreasing the width by 25m I have noticed that the square is the biggest 4 sided shape I will prove this by working out the ...

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