The fencing problem.

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Maths Coursework                                                                        Ajan Pathmanathan 

                                              The Fencing Problem

There is a need to make a fence that is 1000m long. The area inside the fence has to have and give the maximum area.

I will be investigating which shape would give this . I will be investigating the following shapes

  • Rectangles
  • Triangles
  • Pentagons
  • Hexagon
  • Heptagon

Prediction

I predict that as the number of sides increases the area of the shape will also increases

Rectangles

I am going to start investigating different shape rectangles, all which have a perimeter of 1000 meters. Below are 2 rectangles showing how different shapes with the same perimeter can have different areas.

In a rectangle, any 2 different lengths sides will add up to 500 because each side has an opposite with the same length.  Therefore in a rectangle of 100m x 400m, there are two other that are 100m long and 2 sides next tot hem that are opposite each other that are 400m long.

This means that you can work out the area if you only have the length of one side.

To work out the area of a rectangle with a bas length of 200m, I subtract 200 from 500, giving 300 and then times 200 by 300. I can put this into an equation form.

1000 = x(500 - x)

Below is a table of results, worked out using the formula. I have gone down by taking 10m off the base (x) every time.

Join now!

From the above table I will now plot a graph of base length against area to show the relationship between both. (Graph is on next page)

As you can see from my graph it has formed a parabola. According to the table and my graph, the rectangle with a base of 250 meters has the largest area. This shape is also called a square or a regular quadrilateral.

Because I only measured to the nearest 10 meter, I cannot tell whether the graph is true. I will now work out the results using 249m,

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