• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

The Gradient Function

Extracts from this document...

Introduction

        The Gradient Function

Introduction: In this investigation I am going to investigate the gradient function of different lines. I am going find out the gradient of each line and then look at all the different gradients. With

...read more.

Middle

is 9

I can see that each 3 gradients on each line are positive on the lines of y = x (3

y = x  (3             GR 18    GR 8   GR 1

y = 2x (3            GR 32   GR 28  GR 2

y = 3x (3            GR 40  GR 54  GR 3.25

...read more.

Conclusion

  GR 4

y = 2x (2           GR -14  GR -3  GR 13

y = 3x (2           GR -45  GR 33  GR  27.5

Formula: The formula is gr = a

Conclusion: I have found out that gradients increase when the line is made bigger. Also I have commented on different observations I have seen.  

...read more.

This student written piece of work is one of many that can be found in our GCSE Gradient Function section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related GCSE Gradient Function essays

  1. Peer reviewed

    The Gradient Function Coursework

    5 star(s)

    Calculus often deals with the following topics: 1. How to find the instantaneous change (called the "derivative") of various functions. (The process of doing so is called "differentiation".) 2. How to use derivatives to solve various kinds of problems. 3.

  2. Curves and Gradients Investigation

    h = 2x + h (cancel h) As the h value then tends to (gets closer to) 0, so the gradient function for the graph y = x² tends to 2x. This rule can then be applied to any point on the curve and will give the gradient at the point precisely.

  1. Gradient function

    2915.514 9 6561 0 0 0 9.0001 6561.292 0.29160486 0.00010 2916.049 9.001 6563.916 2.916486036 0.001 2916.486 9.01 6590.209 29.20863601 0.01 2920.864 91 68574961 68568400 82 836200 9.2 7163.93 602.9296 0.2 3014.648 9.3 7480.52 919.5201 0.3 3065.067 9.4 7807.49 1246.4896 0.4 3116.224 9.5 8145.063 1584.0625 0.5 3168.125 9.6 8493.466 1932.4656 0.6

  2. Gradient Function

    I have used 3 different fixed points which are (3, 27), (5, 125) and (-3, -27). From my results I can see that the closer I get to the fixed points, the gradient gets closer to 3 times the squared value of X co-ordinate.

  1. The Gradient Function

    If this gradient function, 4ax3 is correct, then the gradient function of 10x4 will be 40x3. To prove that it is 40x3 I am going to draw up a table of values for certain x values. For the curve y=10x4, using the gradient function 40x3 I think the gradients will

  2. The Gradient Function

    1 -1 2 1 -2 2 -1 4 -0.5 Gradients: L1: Gradient at point X = -2 Y2-Y1 X2-X1 = 1.375-0.75 = 0.66 -1.4-(-2.35) L2: Gradient at point X =2 Y2-Y1 X2-X1 = -0.8-(-1.25) = 0.75 2.25-1.65 L3: Gradient at point X = -3 Y2-Y1 X2-X1 =-0.625-0.5 = 0.15625 = 0.16 rounded to 2.d.p -3.05-(-3.85)

  1. The Gradient Function

    Increment Method I have decided to use the small increment method to work out the gradient of all the integer points from one to five on the graph y=x2 because it is very accurate and quite precise enough to get an integer value.

  2. The Gradient Function

    Once again you have to multiply this by 3. This means that the second set of co-ordinates will be (0.81, 1.9683). You then simply substitute it into the equation that is used during the other method of discovering the gradient. However you must subtract the second set of co-ordinates from the first: The Change in Y = 1.9632 -

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work