The Open Box Problem

Authors Avatar

The Open Box Problem

I am going to investigate the size of the square cut which makes the volume of the box as large as possible for any given rectangular sheet of card.

        First I am going to investigate the size of the cut out square which makes an open box of the largest volume for any sized square sheet of card.

Identical squares are cut off the four corners of the card as shown below.

The card is then folded along the dotted lines to make a box.

To find volume the following formula is needed: Volume=length x width x height. To investigate the first square sheet of card, I am going to use a square with the length of each side as 18cm². The practical method would be to make a box and obtain the volume from that, and changing the size of the cut out squares for each trial. For the first trial I will use 2cm² cut out squares at each of the four corners of the card. This would leave me with a length of 14cm for each side. Then I would fold along the dotted lines to make an open box as shown above and then calculate the volume. However this is quite a long method and I could calculate the volume using the net instead of constructing the box.

        However there is an even quicker which I have found which can work out the volume without constructing a box or a net. The length of the cut out square is always the same as the height. Also the length can be calculated by taken the cut length(x2) away from the initial length of each side. As the length of all sides of a square are equal, just multiply the length of one by 2 and then multiply the answer by the height to find the volume of it. This can be done for any square open box. Below I have written a formula of this method. This method helped me find the largest volume of the square much faster because I did not have to construct nets.

Join now!

(length-2χ)² x χ

(χ is the cut out square length)

 Because the size of the square sheet of card is 18cm², the maximum length the cut out square can be is 8cm by 8cm because if I made the cut out square 9 by 9 the whole square would just be separated into four quarters and there would be no base left. Therefore I am going to do 6 trials going up in 1cm intervals starting from 2cm up to 8cm cut lengths.

Below is the table of results I obtained for the 18cm by ...

This is a preview of the whole essay