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To measure the mass of the precipitate (lead iodide) when potassium iodide solution is reacted with lead nitrate solution.

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Introduction

20 - 09 - 05                                                                Jheal Shah ( Chem HL B1)

Chemistry Lab Report - Titration

Aim: - To measure the mass of the precipitate (lead iodide) when potassium iodide solution is reacted with lead nitrate solution.

Apparatus: - Potassium iodide solution, lead nitrate solution, beakers, filter paper, glass stirrer, funnel, pipette, china dish, oven, distilled water, weighing scale.

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Middle

2(ppt)

According to the given equation when 1 part of Lead Nitratereacts with 2 parts of Potassium Iodide we get 1 part of Lead Iodide. Therefore if we use 20ml of Potassium Iodide then we will need to use more than 10ml of Lead Nitrate as it is supposed to be in excess. According to the equation then we would get around 0.46 g of Lead Iodide.

Procedure: - Pipette Potassium Iodide solution as well as Lead Nitrate solution into a beaker in the ratio 2:1. Stir the mixture continuously.

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Conclusion

of filter paper

Weight of filter paper + precipitate

Weight of precipitate

1.

2.

0.72 g

0.80 g

1.21 g

1.20 g

0.49 g

0.40 g

Average = 0.445 g = 0.45 g

There is as error in the reading as the reading is not as expected-

% error = ((0.46 - 0.45)/0.46) * 100 = 2.17 % error

Conclusion: - The precipitate had an average weight of 0.45 g which was just 1 g lesser than the expected value of the precipitate and hence there was an error of 2.17%. This error can be corrected if more care is taken while performing the experiment so as to avoid the systematic errors. There are always random errors some of which cant be avoided.

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