A Comparison of the Energy Released When Different Fuels are burned.

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Chemistry coursework                Shraddha Patel

A Comparison of the Energy Released When Different Fuels are burned

Aim:

To compare and test how well Methanol, Ethanol, Propanol, Butanol and Pentanol will burn and how much energy will be produced.

Introduction:

Alcohols have the general formula CnH2n+1OH.  These atoms are generally part of a homologous chain. I have been set a task to investigate the burning of alcohols.  As the structure shows, the alcohols will burn in oxygen to form carbon dioxide and water vapour.

Alcohol + oxygen                   carbon dioxide + water

Using this equation I will calculate the bond energy formed, bond energy broken and the     H (which will tell me what type of reaction it will be).  The five alcohols that will be burned are: Methanol, Ethanol, Propanol, Butanol and Pentanol.  

Calculations:

  • Methanol

Methanol + oxygen                    carbon dioxide + water

CH3OH    + 1½O2                                    CO2         +          2H2O 

Sum of bond energies broken:

        3(H-C)        3 x 413        =        1239

          (C-O)              358        =          358

          (O-H)              464        =          464

        1½(O=O)       1½ x 498        =          747  +

                                                2808 KJ/mol

Sum of bond energies formed:

        2(O=C)        2 x 805        =        1610

        4(O-H)        4 x 464        =        1856  +

                                                3466 KJ/mol

   H = Sum of βE broken – sum of βE formed

       =         2808  -   3466

       =        -658 KJ/mol

   H is negative; therefore the reaction will be exothermic.

  • Ethanol

Ethanol + Oxygen                  carbon dioxide + water

C2H5OH     +   3O2                         2CO2         +        3H2O

 

Sum of bond energies broken:

        5(C-H)        5 x 413        =        2065

          (C-O)              358        =          358

Join now!

          (O-H)              464        =          464

        3(O=O)        3 x 498        =        1494

          (C-C)              612        =          612

                                                 4993 KJ/mol

Sum of bond energies formed:

        4(O=C)        4 x 805        =        3220

        6(H-O)        6 x 464        =        2784  +

                                                6004 KJ/mol

   H = Sum of βE broken – sum of βE formed

       =        4993  -   6004

       = -1011 KJ/mol

   H is negative; therefore the reaction will be exothermic

  • Propanol

Propanol + oxygen                carbon dioxide + water

C3H7OH  +  4½O2                 3CO2  +  4H2O

Sum of ...

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