Aim: To Determine The Concentration Of a Limewater Solution

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Aim: To Determine The Concentration Of a Limewater Solution

I am going to perform an experiment in which will allow me to determine the concentration, in g dm-3, of limewater given to me containing approximately 1g dm-3 of calcium hydroxide.

I will be performing a simple neutralisation reaction, using HCL, to determine the concentration. I will carry out a titration to determine this.

250cm3 of limewater will be given and the HCl provided is exactly 2.00mol dm-3.

Background Information (Essential AS Chemistry)

Limewater is formed when slacked lime is dissolved in water. The process is started by the vigorous reaction between calcium oxide (limestone) and water. This forms calcium hydroxide (slacked lime). The addition of more water saturates the slacked lime and forms an aqueous solution known as limewater.

Equations

ACID + METAL HYDROXIDE SALT + WATER

Calcium Hydroxide + Hydrochloric Acid Calcium Chloride + Water

Ca(OH)2 aq + 2HClaq CaCl2aq + 2H2O

Therefore the stoichiometric ratio is 2 : 1, hence 2 mol of HCL are required to neutralize 1 mol of Ca(OH)2.

Hydrochloric Acid Concentration

The HCl provided for this experiment is far to concentrated my experiment. It would react with the limewater too quickly hence giving unreliable results. Therefore, I will have to dilute it, using the standardization technique.
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First I would need to find what would be an optimal concentration for the HCl. (molar mass of Ca(OH)2= 74.1)

Converting the g dm-3 to mol dm-3 of the limewater.

Concentration (g dm-3) / Molar Mass = Concentration (mol dm-3)

/ 74.1 = 0.0135

0.01 mol dm-3 limewater concentration (3 s.f)

Therefore as the equation above states for every 1 mol of Ca(OH)2, you would require 2 moles of HCl to neutralize it, I will require my HCl to be of concentration:

0.01 x 2= 0.02 mol ...

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