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Aim: To investigate the rate of cooling of water in two different containers.

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Introduction

PHYSICS LAB REPORT The rate of cooling of water in two different containers Aim: To investigate the rate of cooling of water in two different containers. Apparatus: ==> A testube ==> A beaker ==> 2 digital thermometers (? 0.05?C) ==> A testube holder (wooden) ==> Measuring cylinder ==> Warm water ( around 45 - 50?C) ==> 2 stopwatches Procedure: 1. Pour 20ml of water into a measuring cylinder and then pour it into a beaker. 2. Pour another 20ml into a testube. 3. Place thermometers in both the containers and record the starting temperatures. 4. Start the stopwatches simultaneously. 5. Just when thirty seconds get over, record the temperatures that the thermometers reflect instantaneously.

Middle

==> The same insulation was exposed to both the containers. ==> The atmospheric conditions were kept constant. Safe Test: ==> Be careful while collecting hot water from the kettle. ==> Be careful not to knock over any beaker or container containing hot water. Observation: Raw Data: Table 1: Table showing the gradual decrease in temperature of water held in two containers over ten minutes. Time (secs) Beaker (? 0.05?C) Testube (? 0.05?C) Reading 1 Reading 2 Reading 1 Reading 2 0 44.2 45.8 44.4 46.7 30 43.0 45.4 43.8 46.4 60 42.1 44.9 43.3 46.1 90 42.0 44.5 42.3 45.8 120 41.7 44.0 41.5 45.5 150 41.3 43.7 40.2 44.9 180 39.8 43.2 39.7 44.6 210 38.3 42.8 39.2 44.2 240 38.0 42.1 38.8 43.8 270 37.8 40.9 38.4 43.6

Conclusion

be a need to club the overall change in temperature as an average to figure out which has a higher rate of cooling. Processed Data: Table 2: Table showing the total and average change in temperature over 10 minutes for the respective containers Beaker Testube Reading 1 Reading 2 Reading 1 Reading 2 9.5 11.7 9.3 7.7 Average = 10.6 Average = 8.5 Method used: The final temperature after ten minutes is subtracted from the initial temperature. For eg: 9.5 = 44.2 - 34.7 Conclusion: After an analysis of the results, it can be concluded that the more the surface area of water exposed to atmosphere, the higher the rate of cooling. Thus, the bigger the container, the faster the rate of cooling. ?? ?? ?? ?? Ira Gupta IX-B

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