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An experiment to find the concentration of Calcium Hydroxide by titration with Hydrochloric Acid

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Introduction

An experiment to find the concentration of Calcium Hydroxide by titration with Hydrochloric Acid. The Problem Perform a titration upon Calcium Hydroxide to find the concentration by using Hydrochloric Acid of 3 different concentrations as following 2 molar, 0.5 molar and 0.1 molar. In order to calculate the results must be within 0.05cm3 of each other. Apparatus Burette Volumetric Pipette Beakers Conical Flasks Volumetric Flasks Funnel Clamp Stand White Tile Fair Test For a fair test I will have to make sure that I change the equipment for each test so that the residue of the last test doesn't alter my results and also I must use the same amounts measured as accurately as possible. Preliminary Work The first experiment will have will have to be a titration with the given amounts of Hydrochloric Acid to see whereabouts my equilibrium will lie. ...read more.

Middle

Turn on the tap from the burette and let the HCl run into the pink Ca(OH)2. Shake the flask constantly to evenly distribute the HCl in the solution for accuracy. Keep the tap running until clear patches start to appear in the swirling solution in the flask then slow the tap down and let the HCl drip in one drop at a time, all the time mixing it in, until the solution goes completely colourless. This is the End Point and an equilibrium has been reached, as the solution is neutral. Make a final reading by moving the burette and stand back onto a stool and reading it at eye level, from the bottom of the meniscus. Record the result to 2 decimal places for accuracy. ...read more.

Conclusion

Start Amount End Amount Overall Quantity of HCl required to neutralise:25 TRIAL ** 1 0.00 22.80 22.80 ACTUAL EXP. 1 22.80 45.45 22.65 2 0.05 22.65 22.60 3 22.65 45.25 22.60 Average N/A N/A 22.62 ** Experiment no 1 was my trail using the 0.05moldm-3 solution, this was to make sure that it was in the range required and hasn't been included in the average as it wasn't so accurate. Calculation for concentration of Ca(OH)2 Ca(OH)2 + 2HCl ? CaCl2 + 2H2O 1mol 2mol 1mol 2mol Therefore the exact neutralisation reaction will require 1 mole of Ca(OH)2 to react with 2 moles of HCl. In the equation :- Where V is Volume, c is Concentration and n is number of moles. Let the Calcium Hydroxide be solution A, and the Hydrochloric Acid be solution B. To work out the concentration of A, cA, we need to know all the other factors which make up the formula. Number of Moles in HCl, nB: ...read more.

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