An investigation into the amount of copper deposited on the anode and cathode during electrolysis

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An investigation into the amount of copper deposited on the anode and cathode during electrolysis

I am aiming to discover a relationship between the amount of copper deposited on the anode and cathode during electrolysis in copper sulphate solution.

Background Knowledge

A powerful way to decompose a substance is to pass electricity through it. This process is called electrolysis. Electrolysis occurs when two conductors are submerged in a liquid or solution. The liquid or solution in which the two conductors are submerged must be an electrical conductor. This type of solution is called an electrolyte. A commonly used electrolyte is copper sulphate solution (CuSO4). As this is commonly used for electrolysis this is the solution I decided to use.

The following is information which I have taken from a science textbook. When two conductors are submerged in an electrolyte and a current is passed through, the system is known as an electrolytic cell. When a current is passed through an electrolytic cell, depending upon the orientation of the DC source, one of the conductors becomes the anode (this is positive) and the other becomes the cathode (negative). Different reactions occur at the two conductors. In the electrolyte the molecule, copper sulphate, is in solution and is separated into its two ions, Cu+ and (SO4)-. One of the ions will have a positive charge (cation) and the other a negative charge (anion).

When doing this experiment there are many variables which I could change which would affect the outcome. Here are the input variables which I could change:

Surface area of electrode

Temperature of electrode

Time

Voltage

Strength of copper sulphate solution

If I changed the surface area then it would affect the amount of copper deposited and lost by the copper electrodes. This is because when the electrode has a larger surface area there is more surface for the copper ions to dissolve into the solution from. It is important to keep the surface area of the electrodes the same because the greater the surface area the greater the loss in mass at the anode. I can keep the surface area of the electrodes the same by always using the same sized electrodes and covering the same amount of each with copper sulphate solution. Although I cannot make sure that the surface area covered is exactly the same for each one, I can be fairly accurate and I believe that any differences would be to slight to effect the results.

I know from previous work that if an electrode gets hot it will expand and so I must ensure that all experiments are carried out at the same temperature. To do this I will always carry out my practical at room temperature.

Time is another input variable. The longer the electrodes are in the solution the more mass will be lost at the anode and gained at the cathode, therefore I will need to keep the time constant throughout my experiments. I have decided upon ten minutes as it will enable me to carry out all my experiments and I believe the time span will create good variability between results.
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It is important to keep the strength of the copper sulphate solution the same throughout because the stronger the solution the more copper ions there will be to take electrons from the cathode, therefore speeding up electrolysis. To keep my test fair I have decided to keep the strength of the solution at 0.5 moles each time.

I have decided to use voltage as my input variable. The voltage is directly proportional to the amount of mass lost and gained at the anode and cathode because with a greater charge, the copper at the anode has to ...

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