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Viscosity of Honey

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Introduction

Viscosity of Honey Plan For this assignment I will carry out an experiment to find the viscosity of honey. In the experiment I will drop a ball bearing into a measuring cylinder containing honey, and I will time how long it takes for the ball bearing to reach the bottom of the cylinder. For this experiment I am going to use the following equipment: Measuring Cylinder Ball Bearing Honey Stop Clock Micrometer Screw Gauge Digital Scale Magnet First I am going to weigh an empty measuring cylinder, then weigh a measuring cylinder with filled with honey and subtract the mass of the measuring cylinder from the mass of the measuring cylinder filled with honey to get the mass of the honey. Then I will measure the diameter of a ball bearing using a micrometer and I will measure the volume of the honey. Then I will drop the ball bearing into the cylinder containing the honey and using a stop clock time how long it takes for the ball bearing to pass the region of terminal velocity in the cylinder: I will set the equipment up as shown: To make the experiment a fair test I am going to time how long it takes for the ...read more.

Middle

C. Radius2 (r2) of steel ball bearing Time taken to pass region of terminal velocity 0.0082 m 2.45 seconds 0.00252 m 4.41 seconds 0.0022 m 9.07 seconds 0.00152 m 11.46 seconds 0.0012 m 17.98 seconds 0.000752 m 31.66 seconds The distance of the region of terminal velocity is 10cm. The terminal velocities of the ball bearings are as follows: Speed of 0.0082 m ball bearing = 0.040816326 ms-1 Speed of 0.00252 m ball bearing = 0.022675736 ms-1 Speed of 0.0022 m ball bearing = 0.011025358 ms-1 Speed of 0.00152 m ball bearing = 0.009560229446 ms-1 Speed of 0.0012 m ball bearing = 0.005561735261 ms-1 Speed of 0.000752 m ball bearing = 0.003158559697 ms-1 The mass of the cylinder = 0.11597 kg. The mass of the cylinder + honey = 0.2355 kg. The mass of honey = 0.2355 - 0.11597 = 0.11953 kg. The volume of the honey = 0.00008499999582 m3. The density of honey = 0.11953/0.00008499999582 = 1406.235363 kg/m3. The mass of 0.0082 m steel ball bearing = 0.01671 kg. The volume of 0.0082 m steel ball bearing = 4/3 ? r3 = 4/3 ? x 0.0083 = 0.000002144660585 m3. ...read more.

Conclusion

y1 = 0.011 y2 = 0.019 x1 = 0.000003 x2 = 0.0000056 Gradient = (y2 - y1) / (x2 - x1) = (0.019 - 0.011) / (0.0000056 - 0.000003) = 3076.923077 The gradient of the 30?C graph is 3076.923077, and now I can work out the viscosity of the honey at 30?C using: ? = 2g (? steel - ? honey) / 9 x Gradient ? = 2(9.8) (7791.442673 - 1406.235363) / (9 x 3076.923077) = 19.6 (6385.20731) / 27692.30769 = 4.519307842 The viscosity of honey at 30?C is 4.519307842 Nsm-1. One thing my results show is that the viscosity of the honey is lower at 30?C than it is at room temperature, suggesting that the viscosity of the honey decreases with a rise in temperature and increases with a fall in temperature. The reason why I got inaccurate measurements is due to human error, the time it took me to start and stop the stop clock, one way to improve my measurements is to use a computer to measure the time it took for the ball bearing to pass through the region of terminal velocity. This and other similar errors were inevitable. Physics 1 Shumon Miah Shumon Miah ...read more.

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