Chemistry Coursework-Determination Of The Atomic mass of Lithium
I am going to determine the relative atomic mass of lithium by two different methods:
- Method 1: I will measure the volume of hydrogen produced when a known mass of lithium reacts with water.
- Method 2: I will titrate the solution of lithium hydroxide produced.
Results from method 1:
0.13g of lithium reacted with 100cm3 of water to produce 238cm3 of hydrogen gas.
As I know that 1 mole of hydrogen gas occupies 24dm3.
- Calculate the number of moles of hydrogen that I collected.
238/24000 = 9.916*10-3
To check this I will use the formula below.
V=nRT
- Deduce the number of moles of lithium that reacted.
The ratio of lithium to hydrogen is 2:1 so the moles of hydrogen have to be multiplied by 2 to get the correct answer.
0.009916666*2 = 0.019833333 moles
- Using the values from above and the original mass of lithium, calculate the relative atomic mass of lithium.
Moles = Mass
Ar
Ar = Mass
Moles
Ar = 0.13
0.0198333
Ar = 7.090914248
Results from method 2:
- Titration of aqueous lithium hydroxide with 0.100 mol dm3 Hydrochloric acid.
0.13g of lithium produced 100cm3 of lithium hydroxide.
25cm3 needed 43.5cm3
25cm3 needed 44cm3
25cm3 needed 43.8cm3
On average, 25cm3 of lithium hydroxide required 43.76cm3 of 0.100 mol dm3 hydrochloric acid to neutralise it.