Determination of the formula of Hydrated Iron (II) Sulphate Crystals

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Chemistry Coursework

Determination of the formula of Hydrated Iron (II) Sulphate Crystals

Safety

To ensure that my experiment is safe, I will carry out the following precautions:-

  • Goggles should be worn at all times to protect my eyes from the chemicals or in case another accident occurred.
  • Keep all glass materials away from the edge to prevent any breakages and sharp pieces on the floor. If any were to break clean immediately.
  • If any liquid were to be spilled on the floor immediately dry it up to prevent someone from slipping.
  • Wear gloves at all times when handling chemicals.
  • Some chemicals are highly flammable, so make sure not to expose to a direct flame throughout the whole experiment.
  • Potassium permanganate is an oxidising agent and if it got contact with combustible material may cause fire. It is also dangerous with sulphuric acid and may cause a fire.
  • Iron sulphate can be a irritant to the eyes and skin
  • Sulphur dioxide is very toxic when inhaled. Irritating to the eyes and respiratory system.
  • Sulphuric acid causes severe burns and irritation to skin. It is also dangerous with water and potassium where dangerous reactions can take place.

Analysis

Method one

  • Mass of crucible: 9.87g
  • Mass of crucible and FeSO4.xH2O before heating: 11.32g

  • Mass of FeSO4.xH2O before heating         = Mass of crucible and FeSO4.xH2O - Mass of crucible
  • = 11.32g – 9.87g = 1.45g

  • Mass of crucible after heating (2mins): 10.7g

  • Mass of FeSO4.xH2O after heating (2mins)         = Mass of crucible after heating (2mins) - Mass of crucible
  • = 10.7g - 9.87g = 0.83g

  • Mass of H2O lost        = Mass of crucible and FeSO4.xH2O before heating - Mass of crucible after heating (2mins)
  • = 11.32g - 10.7g = 0.62g

Molar ratio = 0.0055mol/0.0055mol = 1            :        0.0344mol/0.0055mol = 6.25 = 6        

I divided by 0.0055mol because is it the smallest number of moles out of the two.

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  • Therefore we know there are 6 moles of H2O for every 1 mole of FeSO4


Method two

  • Mass of weight boat: 1.87g
  • Mass of weighting boat and FeSO4: 4.85g
  • Mass of FeSO4         = Mass of weighting boat and FeSO4 - Mass of weight boat
  • = 4.85g - 1.87g = 2.98g

  • Moles of KMnO4                 = concentration*volume
  • Concentration: 0.0100 moldm-3*
  • Volume: 18.85 cm2/1000 = 0.01885dm3
  • Moles                                = 0.0100 moldm-3*0.01885
  • = 0.000188 = 0.00019 mol

As we can see from the ...

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