Determination of the Relative Atomic Mass of Calcium

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Determination of the Relative Atomic Mass of Calcium

In this experiment, I will determine the relative atomic mass of calcium by two different methods.

* By measuring the volume of hydrogen produced.

* By titrating the lithium hydroxide produced.

Method 1

* 0.10g of calcium used.

* 100cm3 of distilled water used.

Results

Method 1

Mass of Calcium (g)

Total volume of gas produced (cm3)

0.10

37

* Starting point of water in cylinder = 238cm3

* Ending point, after reaction complete, of water in cylinder= 201cm3

* (238 - 201 = 37) Deduction of 37cm3, therefore 37cm3 of hydrogen gas produced.

1 mol of gas occupies 24000 cm3 at room temperature and pressure.

Ca (s) + 2H2O (l) --> Ca(OH)2 (aq) + H2 (g)

* Number of moles of hydrogen = volume of hydrogen / 24000

= 37/24000 = 0.0015416 mol

= 0.001542 mol (4sf)

* Number of moles of calcium = 0.001542 (ratio 1:1 with hydrogen)

* Relative atomic mass of calcium = Mass of