Determination of the relative atomic mass of Lithium.

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Determination of the relative atomic mass of Lithium

Implementing

For all my results I have decided to use three significant figures. This is because the apparatus I was told to use for the experiment gave me results to three significant figures. There was, therefor, no point in calculate to any further accuracy as this would just define a figure that has already been calculated to a specific depth of accuracy.

 

Results

Method 1

Method 2

Average 42.2 cm3

Analysing

Method 1

Calculate the number of moles of hydrogen.

1)   175  = 0.00729                   Number of moles = Amount of gas produced

    2400                                                              2400

This was calculated to find out the number of moles in the Hydrogen gas that had produced.

Deduce from this the number of moles of Lithium.

2) The number of moles of Lithium = 0.00729 x 2= 0.0146        

If you look at the chemical equation–

2Li(s) + 2H2O(l) ------→ 2LiOH(aq) + H2(g)

You can see that the molar ratio of number of moles of hydrogen to number of moles of lithium is 1:2. As I had already calculated the number of moles for Hydrogen, I can multiply it by two and this will give me the number of moles of Lithium.

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Using your values above and the original mass of Lithium, calculate the relative atomic mass of lithium.

3) 1.09 = 7.13                                      Relative atomic mass= Mass used in grams

    0.146                                                           Number of moles

From the amount of lithium used and the number of moles of lithium. I used the above equation to calculate the relative atomic mass of lithium.

Method 2

Calculate the number of moles of HCl used in the titration.

      (Average volume)

1) 42.7 x 0.1= 0.00422                Number of moles of ...

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