Determining the Solubility of Calcium Hydroxide.

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Determining the Solubility of Calcium Hydroxide

By Osman Khan

Lee 12

Apparatus

0.015mol dm-3 calcium hydroxide

0.3mol dm-3 hydrochloric acid

Distilled water

Methyl orange indicator

50cm3 burette

250cm3 volumetric flask

Pipette and pipette filler

Beaker

Measuring cylinder

Conical flask

Clamp Stand

Filter funnel

Method

  1. Using a measuring cylinder put 25cm3 of hydrochloric acid into a 100cm3. Using some distilled water rinse out the measuring cylinder and pour the contents into the same beaker containing hydrochloric acid.
  2. Next transfer the contents of this beaker to a 250cm3 volumetric flask. It may be necessary to use a volumetric flask, and if so rinse this out once it has been used. Again rinse out the beaker using distilled water and pour the contents into the volumetric flask.
  3. Once the hydrochloric acid / water solution is in the volumetric flask, fill the volumetric flask with distilled water until you are about 2-4cm3 from the graduation mark. At this point add water to the volumetric flask using a pipette until the bottom of the meniscus is just touching the graduation mark. Stopper the flask and invert it several times to mix the contents together.
  4. Now, using the pipette and pipette filler, withdraw 25cm3 of the hydrochloric acid/ water solution and place this into a conical flask. Once this is done add 3 drops of methyl orange indicator to the contents.
  5. Next, rinse out the burette using distilled water and then rinse it using calcium hydroxide. After doing so fill up the burette using calcium hydroxide. If an air bubble is present near the jet, run out some liquid until the bubble is removed
  6. Record the initial burette reading to two decimal places and then start titrating. Keep swirling the contents of the flask as you add the alkali to the acid until there is a colour change of the solution. This is a rough titration and should then be repeated more accurately until the results lay within 0.1cm3 of each other.

Quantities of Materials to use

2HCl(l) + Ca(OH)2(l)                CaCl2(l) + 2H2O(l)

From the above equation it is clear that I require 2 moles of hydrochloric acid to react with 1 mole of calcium hydroxide. Therefore I will use a hydrochloric acid solution that is twice as concentrated as the calcium hydroxide.

The concentration of the calcium hydroxide is 0.015mol dm-3. Therefore the hydrochloric acid needs to be a concentration of 0.03mol dm-3. Originally the concentration is 0.3mol dm-3 so I need to dilute this by a factor of 10. As the volumetric flask holds 250cm3 I require 1/10 of this to be hydrochloric acid. I will therefore use:

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1/10 x 250 = 25cm3 hydrochloric acid

I will therefore need 225cm3 water to make up this concentration as well as ncm3 of water to wash out the other apparatus.

I predict that I will need a volume of about 25cm3 of calcium hydroxide for each titration, but can not say the exact total amount I require as I do not know how accurately I will be able to carry out the titration.

As well as this I require 3 drops of methyl orange indicator per titration and once again I can therefore not say the total amount I need as I ...

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