Deviation of Light by a Prism.

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Nigel Evans

Physics Coursework – “Deviation of Light by a Prism”

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Deviation of Light by a Prism

Aim

The aim of this investigation is to test using a prism how the angle of deviation (how far the light ray is deviated from its original position) is affected by varying the angle of incidence (where the light ray goes into the prism), and whether this has any relation to the angle of emergence (where the light actually comes out of the prism).

Planning

I firstly need to conduct theoretical work and a preliminary investigation to test what is going on and to get a clearer view of the aspects of the investigation. In my theoretical work I will have to use the geometry of triangles and Snells Law. For Snells law to work, I will need to know the refractive index of the glass that I am using. To do this I will use a glass block of the same glass as the prism, and then use sighting pins (and light) to pinpoint the incident ray and the emergence ray and then find the angle of refraction. A more detailed description of how this experiment is going to work can be seen below.

To find the refractive index of the glass that I will be using in the actual experiment, I set up a glass block that was of the same type of glass as the prism, and lined up sighting pins through it. This enables me to draw the angle of incidence (measured from the Normal (dotted line below), a line at 90° to where the incident ray strikes the glass block) and this also enables me to draw the angle of emergence (where the light exits the prism). I then would connect both the lines up and draw the path, which the ray actually takes through the prism (the refracted ray). After this I would measure the refracted ray, again the is measured from the same normal, and then I would use Snells Law to calculate the refractive index of the prism.        I will be measuring all angles using a 360° protractor.

Snells Law =

(Where “i” is the angle of incidence and “r” is the angle of refraction, and “n” is the refractive index of the material in question) This is also assuming that light is travelling form a vacuum into the glass, even though it will actually be travelling from air into glass. I have considered this fact to be negligible because the refractive index of air is roughly equal to 1 (about 1.003) and substituting this value into the formula gives the same refractive index as it would for a vacuum.

This will enable me to find the refractive index of the borosilicate crown glass. I will repeat this experiment using both light and sighting pins. This experiment will be repeated in order to obtain an accurate average thus ensuring an accurate figure for the refractive index of the glass. I will also compare my averaged answer to the one in a data book and average the two together to obtain an accurate refractive index of the glass that I will be using. Below is a table of values that I collected for both the light method and the sighting pin method. The actual drawings of these results can be seen on the next few pages.

The Data Book (“Table of physical and chemical constants – 14th addition” – By “G.W.C. Kaye and T.H.Laby”) that I consulted to check if this value was correct gave an answer of 1.509. I have averaged the one obtained above and the one given by the data book to obtain a refractive index value for the glass I am using of 1.51.

Another Preliminary investigation which I under took was to see actually which path the ray of light took through the prism, so I could make my diagrams more accurate and get a clearer view of exactly what the investigation would entail.

Prediction

Until I actually commence with my calculations to see how the angles vary compared to one another, I can offer no prediction based on initial knowledge, as my knowledge what happens to light in a prism, and how the angles change with respect to one another is limited.

Hypothesis

Above is a diagram for the actual path that a ray of light takes through a prism.

The letter “I” represents the angle of incidence.

R1 represents the first angle of refraction.

The second angle of refraction is represented by “R2”.

The letter “E” represents the angle of emergence.

The Greek letter delta, “δ” represents the angle of deviation.

On the next page is a larger diagram of the above prism, the advantage of this being that the letters and angles that I will be referring to throughout my experiment can be seen here in clearer detail.

Example Calculation of Deviance 1:

Firstly I need to specify an angle of incidence, for this example calculation I will be using 40°. This will be measured from the normal (line at 90° to point where incident ray strikes). As the light enters the prism it is refracted so I need to use Snells Law to work out the angle of refraction:

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Therefore sin r = sin 40 / 1.51

= 0.42569

Sin-1 0.42569 = 25.2° This is the first angle of refraction, R1.

I know that the angle of refraction is at 90° to the prism, and so I can work out the angle that R1 makes with it using 90 – R1.This gives:

90° – 25.2° = 64.8° (call this angle “a”)

I also know the angle at the top of the prism because this is always 60° for the type of prisms that we are using, so I can use a rule from the geometry of ...

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