Enzymes at work

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Dean Blewitt

Enzymes at work

The aim of my investigation is to find out what pH the enzyme named peroxidase works best at. We can find the enzyme peroxidase if we grind up celery, or most other animal and plants. A chemical reaction in plants and animals produce hydrogen peroxide, this can poison them if it is allowed to accumulate. The enzyme peroxidase acts as a catalyst for decomposing hydrogen peroxide, it is broken down into water and oxygen. The reaction is:

2H20 = 2H20 + O2

(Aq)        (L)        (G)

I plan to measure the amount of oxygen given off by the celery at different pHs and whichever pH helps the enzyme produce the most oxygen. Before I do this I must do a preliminary plan to see what my other variables should be so that I can get the best results.

I predict that the optimum pH will be around 7 because if it goes any lower or higher than this it could change the enzymes shape and/or charge properties of the substrate so that either the substrate cannot bind to the active site or it cannot undergo catalysis. Different enzymes have different optimum pHs and it is hard to say what it will be because some enzymes work best at low temperatures and others at high temperature. As you can see from the graph the two different enzymes, represented by red and green lines, have a different optimum pH. When the pH is altered is will become denatured or it may be optimum it depends on what is the best pH that the enzyme responds to.

I believe it will be 7 because this is in the middle, 7 isn’t too high or too low but it could be wrong depending on the enzyme. I think it is pH7 because this is the pH of pure water, the enzyme peroxidase is found in your cells and most of the body is made up of water, I am expecting the cell to be of the pH water, and to ensure that the enzyme works at its optimum condition it will work at 7. The enzyme will be working at the pH 7 the majority of the time and our bodies will have adapted to suit the enzyme and help it work better.

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In my preliminary plan, I will investigate how much oxygen is produced when the enzyme hydrogen peroxide and some slices of potato are added together. This experiment is very similar to the celery one with the exception that it is potato slices not celery slices. This experiment will give me an idea on what I should change or keep the same. It will also make me aware of the other variables in the experiment and what I need to change about them to get the best results. The enzyme is also strongly affected by temperature; hydrogen bonds are easily ...

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