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# Experiment on The Use of Analytical Balance in Determining the Water Content of a Given Hydrated Salt

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Introduction

Title The Use of Analytical Balance in Determining the Water Content of a Given Hydrated Salt. Objective - Use of analytical balance to weight a given hydrated salt as accurate as possible to determine the weight of water in the salt. - Train us to handle the analytical balance to weight different object. Data / Results Individual Result: Material Two-decimal Balance(g) Analytical Balance(g) Pencil 4.28 4.2863 20cent coin 5.71 5.7110 3cm x 2cm paper (Without sign) 0.04 0.0446 3cm x 2cm paper (With sign) 0.04 0.0447 Material Two-decimal Balance(g) Analytical Balance(g) Pencil 9.53 9.5395 20cent coin 5.63 5.6318 3cm x 2cm paper (Without sign) 0.02 0.0264 3cm x 2cm paper (With sign) 0.02 0.0316 Group Result: Material Two-decimal Balance(g) Analytical Balance(g) Biker + Test Tube 53.49 41.5471 Biker + Test Tube + Hydrated Salt 54.89 42.0562 Biker + Test Tube + Dehydrated Salt 54.74 41.8946 54.74 41.8924 Water Content of Hydrated Salt 0.15 0.1616 Analysis and Calculations Analysis: This experiment is to find out the mass of water in the hydrated salt (CuSO4 x *H2O). ...read more.

Middle

So, from the above example given, we can conclude that, the analytical balance is more accurate then two-decimal balance. Calculation: Mass of Test tube (Mass of test tube + biker) - (Mass of biker) Analytical balance: 41.5471 - 36.0436 =5.5035g Two-decimal balance: 53.49 - 48.89 =5.50g Mass of Hydrated salt (Mass of test tube + biker + hydrated salt) - (Mass of test tube + biker) Analytical balance: 42.0562 - 41.5471 =0.5091g Two-decimal balance: 54.89 - 54.39 =0.5g Mass of Dehydrated salt (Mass of test tube + biker + dehydrated salt) - (Mass of test tube + biker) Analytical balance: 41.8946 - 41.5471 =0.3475g Two-decimal balance: 54.74 - 54.39 =0.35g Mass of Water (Mass of hydrated salt) - (Mass of dehydrated salt) Analytical balance: 0.5091 - 0.3475 =0.1616g Two-decimal balance: 0.50 - 0.35 =0.15g Question Q1. H=1.0079 S=32.065 Cu=63.546 O=15.9994 CuSO4=159.6085 H2O=18.0153 Analytical balance: Weight of water in salt= hydrated salt - dehydrated salt = 0.5091 - 0.3475 = 0.1616g Two-decimal balance: Weight of water in salt= hydrated salt - dehydrated salt = 0.50 - 0.35 = ...read more.

Conclusion

To start weighing, we place the biker as a weighing container on the weighing pan and remember to close the chamber doors after opened it. After putting the weighing container, to clear the readout just simply pressing "TARE" button will do. After that, we add the substance to be weighed, but make sure that the substance did not split on the weighing pan, because this will affect the reading of the readout. If necessary, it is advisable to take out the container from the weighing chamber when adding the substance to be weighed, did not press "TARE" button before weigh the substance that just added in the container. Put back the container on the weighing pan after added the substance, remember to close the chamber doors. The readout will show the net weight of the substance just added. After recorded the readout, take out the container from the weighing chamber and clear the readout by pressing the button "TARE". Again, remember to close the chamber doors and ensure that the weighing pan is cleared. To turn off the analytical balance, press "off". Bear in mind, each time using the analytical balance must handle it with care. ...read more.

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