• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Factors affecting the resistance of resistance paper.

Extracts from this document...

Introduction

Physics Coursework

Factors affecting the resistance of resistance paper

-Planning my investigation

Variables:

  • Length of resistance paper
  • Shape of paper
  • Thickness of paper
  • Width of paper
  • Type of paper

Experiment:

My independent variable will be the length of the paper, and I will measure this from 1cm into the paper each side. I will measure at 4cm intervals (e.g. 4,8,12,16,20,etc.)

My controlled variables will be the shape of the paper, the thickness, the width, and the type.

My dependent variable will be the resistance of the paper.

I will not need any safety equipment as the experiment is at a low voltage, and my apparatus is safe and reliable.

Diagram:

image06.pngimage05.pngimage17.pngimage02.pngimage18.pngimage07.pngimage07.pngimage01.pngimage07.pngimage16.pngimage04.pngimage14.pngimage14.pngimage03.pngimage00.png

image08.png

image09.png

image10.png

image11.png

image12.png

image13.png

image15.png

I will make sure that my controlled variables are accurate (e.g. very carefully controlled) so that the experiment is fairer. I will take each result three times and make an average, to have a higher degree of accuracy and eradicate anomalies.

Apparatus:

  • 6 x wire
  • 1 x battery
  • 1 x voltmeter
  • 1 x ammeter
  • 1 x 470Ω safety resistor
  • 1 x resistance paper (30cm x 5cm)

image19.png

Prediction:

I predict that the longer the paper is, the higher the

resistance will be.

...read more.

Middle

407

8

814

12

1221

16

1629

20

2036

24

2443

28

2850

To find these, I used the formula:

R24 = 6/7 x 2850 = 2442.9

(but for each value I put the resistance I wanted to find at the beginning e.g. R24, R20, R16 etc. Then I divided this number by 28(which I could round down to 7), the value which I already knew, and multiplied this all by the value of 28, which was 2850.)

Therefore, the formula is:Rn = n/28 x 2850

I used this formula to make all the predictions in the table above. These predictions rely on the fact that in this experiment, resistance increase and length increase are proportional. The reason that I think this is that during my last experiment, where I used a wire with variable length instead of resistance paper, and it was proportional. Therefore, as this experiment is very similar (substituting the wire for resistance paper), I think the graph and results will also be similar.

...read more.

Conclusion

        ii) reliability of my apparatus

        iii) strong correlation of results

If I did this particular experiment again, I would make very few changes. One change I may make would be to increase the amount of results in my previous experiment, which I based my prediction upon. If I had done this, I could have made an average and based my predictions upon this. The danger of not doing this is that I could have based my predictions on an anomaly. I did not use just one result, but I did use only a few, which may have been the cause of the slight difference between my predicted results and my obtained results. Had I done this, I may have increased the reliability of my predictions, but this would not have affected my obtained results, so if I had only based my predictions on one result, it would not have been very important. As it was, my prediction was fairly accurate, so I obviously did not use an anomaly. This brought to the conclusion that my experiment was a success.

...read more.

This student written piece of work is one of many that can be found in our GCSE Electricity and Magnetism section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related GCSE Electricity and Magnetism essays

  1. Marked by a teacher

    The factors affecting the resistance of a metalic conductor.

    4 star(s)

    Whereas a wire with a longer distance will have more atoms for the electrons to hit and the resistance gradually increases as a result. * In the case of the cross-sectional area; a wire with a greater area allows more electrons to flow through it as well as having more channels for the electrons to flow through it.

  2. Discover the factors affecting resistance in a conductor.

    my main experiment, hopefully to a higher degree of accuracy (since in this circuit, other factors were causing resistance, not just the wire). Secondary Sources of information This is a table that I found in a similar project, that shows the resistance when a current was applied to Teledeltos Paper.

  1. An investigation into the factors affecting the resistance of a wire.

    hit a fixed vibrating atom, thus slowing it down and reducing the current of the electricity. I have found from prior research and experimentation that if I were testing different widths of wire, the thinner ones would have more resistance.

  2. Factors affecting Resistance of a wire

    1.79 1.8 1.8 1.8 1.80 0.994444444 [Hand drawn graph here] Table & Graph for 26 SWG Length (cm) 26 SWG volts 26 SWG amps Average Resistance (?) Test 1 2 3 Average Test 1 2 3 Average Measured in seconds Measured in seconds 10 0.35 0.28 0.30 0.31 0.4 0.4

  1. Length vs Resistance

    Finally, to make sure the results I get are reliable, I will make sure to test the voltage and current for each length of wire at least three times. I will then add the three results together and divide them by three so that I can get an average result for each length I test.

  2. An Investigation into how the resistance of a piece of graphite paper is affected ...

    > I will attach the clips to each end of the graphite paper. I will start the measurement of 29cm from clip to clip. > I will attach the 0-1mA shunt to the ammeter. > I will read from the ammeter each time I cut down the width by using scissors.

  1. Factors Affecting the Efficiency of a Wind Turbine

    Wind energy delivers the kinetic energy to the blades, which rotate. Calculating the kinetic energy of the wind is easy, we use the formula (K.E = 0.5 mv2). The faster it moves the higher the kinetic energy. We use the kinetic energy to find a rate at which this energy is delivered to a wind turbine.

  2. Investigation into the factors affecting the resistance of wire

    0.1 0.1 0.51 0.52 0.52 0.193564605 0.2 0.031415927 2.027E-05 Copper 36swg 350 0.1 0.09 0.09 0.46 0.48 0.46 0.200181159 0.2 0.031415927 1.79682E-05 Copper 36swg 400 0.1 0.1 0.1 0.42 0.41 0.4 0.243999226 0.2 0.031415927 1.91637E-05 Copper 36swg 450 0.11 0.1 0.1 0.35 0.37 0.36 0.287444587 0.2 0.031415927 2.00674E-05 Copper 36swg

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work