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Find out how the concentration of the reactants affects the rate of reaction between hydrochloric acid and sodium thiosulpahte.

Extracts from this document...

Introduction

Ketan Patel 11F6 Science Coursework Mr Murphy Set 2 Investigating the Rate of Reaction between Sodium Thiosulphate and Hydrochloric Acid PLANNING Aim My aim is to find out how the concentration of the reactants affects the rate of reaction between hydrochloric acid and sodium thiosulpahte. Apparatus * Two measuring cylinders (25mls) * One small measuring cylinder (10mls) * One flask * Two small beakers (100mls) * One felt tip marker pen * One sheet of paper * One stop clock * Hydrochloric acid * Sodium thiosulphate * Supply of water Diagram Prediction I predict that when the volume of hydrochloric acid is decreased and water replaces the volume of hydrochloric acid that has been taken away the reaction rate will be slower. I predict the reaction rate will be slower because of my experience to when I have drank a drink which hasn't been diluted and when I have drank a drink that has been diluted with water. When you purchase a bottle of Vimto when you pour the drink into the cup you need to add three quarters of water more than the drink because it will decrease the sharpness of the taste. But if you drink the Vimto undiluted you will find that the drink is very strong. I also predict that the chemical reaction between sodium thiosulphate and hydrochloric acid will react at room temperature. I predict that there is no need for any deliberate action towards the chemicals to cause the reaction because from reading the collision theory I know that the particles must collide with the minimum energy called the activation energy. Fair Testing To make the investigation a fair test I will carry out the following precautions: - * I will use two separate measuring cylinders for each of the chemicals (sodium thiosulphate and hydrochloric acid) * I will use two separate small beakers for each of the chemicals (sodium thiosulphate and hydrochloric acid) ...read more.

Middle

The investigation was which fuel out of paraffin, methylated spirit and olive oil could heat up water the most in five minutes. Out of the three fuels the paraffin was the best at heating up the water compared to the results of the other fuels and the volume of the paraffin was used up the most out of the other fuels. The results of the investigation were: - PARAFFIN WIEGHT AT BEGINNING = 119.1 GRAMS END = 116.9 GRAMS DIFFERNCE = 2.2 GRAMS TIME (SECONDS) TEMPERATURE OF WATER (DEGREES CELCIUS) 0 21 60 25 120 28 180 29 240 31 300 33 METHYLATED SPIRIT WIEGHT AT BEGINNING = 119.1 GRAMS END = 117.9 GRAMS DIFFERNCE = 1.2 GRAMS TIME (SECONDS) TEMPERATURE OF WATER (DEGREES CELCIUS) 0 21 60 24 120 26 180 27 240 29 300 30 OLIVE OIL WIEGHT AT BEGINNING = 119.1 GRAMS END = 118.7 GRAMS DIFFERENCE = 0.4 GRAMS TIME (SECONDS) TEMPERATURE OF WATER (DEGREES CELCIUS) 0 21 60 22 120 24 180 25 240 26 300 28 As you can see the results of the past investigation shows that the paraffin was the most effective at heating up the fuels and the volume of the paraffin was used up the most. The reason why the paraffin gave of more heat is because the paraffin is more flammable than methylated spirit and olive oil. And also the reason for paraffin being more flammable than the other fuels is because paraffin has smaller hydrocarbons than the other fuels so it was a lot more easier for the hydrocarbons to react with oxygen because it has smaller hydrocarbons. That is also the reason why more of the volume of the fuel was used up because the chemical bonds were is to break. The smaller the bonds in the volume the more small bonds in the paraffin. Therefore the volume of the paraffin will be more concentrated than the other fuels because it has smaller bonds. ...read more.

Conclusion

Even though my results are accurate and reliable if I were to do the investigation again I would do each individual test five times to make sure I get a more accurate and reliable results. This will make sure I get accurate readings to when I come to work out the average result of each individual test so that my results are sufficient enough for me to be able to reach a firm conclusion. I would also have used a laser over the top of the flask to measure when the cross has completely been blotted out by using a pad underneath the flask wired to a computer. The pad underneath the flask will stop the clock when the pad underneath the flask stops receiving the laser light when a certain amount of sulphur particles are formed in the volume. When the sulphur particles have formed and the pad stops receiving laser contact then a current will go from the pad into the computer to stop the stop clock. I am also happy to confirm that the results I have obtained do not contain any odd results. Additional Experiment To extend my investigation in this subject I could use a catalyst for a reactant to see how efficient the catalyst is compared to other results as the catalyst is used again. This will tell me the efficiency of the catalyst. For example I would mix 25mls of reactant A with the reactant B (catalyst) and measure the time it takes for the cross to be blotted out and record the result. Then I would repeat the experiment another 9 times and record the results. From the results at the end I would be able to see if the catalyst is deteriorating or staying the same. The aim of this experiment would be to find out if the catalyst is at all effected when it us used. You will be able to see this if the results are plotted onto a graph. KETAN PATEL ...read more.

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