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find out if changing the surface area of a potato chip will have an affect on the amount of Oxygen produced when the potato chip reacts with Hydrogen peroxide.

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Biology coursework This report is about the enzyme called Catalase and how it reacts with Hydrogen Peroxide. This enzyme can be found in any organism, its breaks down hydrogen peroxide into oxygen and water in the organism, these products are very useful to all living things and the organism can make use of these things. Here is the chemical equation for what the enzyme does. HYDROGEN PEROXIDE OXYGEN +WATER H202 02 + H 20 Hydrogen peroxide is a very dangerous poison and if it could not be broken down by the enzyme Catalase then that organism would not survive. Key Factors These are the factors that could affect the results produced by the experiment, it would either show too much or too little oxygen produced. Vol- Concentration Temperature Surface area of chip Temperature of enzyme Time enzyme is exposed to Peroxide Enzymes Old/New potato I will be investigating the temperature factor and seeing how it affects the enzyme activity. I will vary the temperatures to see what the enzymes optimum temperature is and when the enzyme starts to denature. Fair test To make it a fair test I will only change one factor and keep all the other factors constant as it could effect my results. An example of an unfair test where more than one factor is changed is shown below. Prediction I predict that the enzymes optimum temperature is roughly about 40oC. I will explain this prediction in a bit more depth in the following diagram. ...read more.


2 Variables Dependant - Volume of Oxygen Independent - temperature The above means that if the temperature changes then the volume of Oxygen changes. Therefore the volume of Oxygen is dependant on the temperature. From the graph above I can deduce that the optimum temperature for the enzyme to work at is 40oC. As the temperature increased up to 40oC, the graph showed positive correlation; an increase in enzyme activity. After the temperature of 40oC the graph showed negative correlation; a decrease in enzyme activity because the enzyme has started to denature. At 40oC the enzyme was working at its best as it produced the most oxygen when reacting with the peroxide, it produced an average of 5.10cm3 Which was the most gas produced in the experiment. From the Pre-tests carried out I have concluded that the best strength Peroxide to use is 20-Vol. I also concluded that the optimum temperature was 40oC. Relationship Up to the temperature of 40oC the graph showed positive correlation, after that temperature the graph started to show negative correlation. In my prediction I expected the results to look like this, I predicted that up to 40oC the enzyme activity would be increasing and after that temperature the enzyme activity would decrease. I also predicted that the optimum temperature for the enzyme would be 40oC. I can back up my pre-test results by using my scientific knowledge. My knowledge tells me that between the temperatures of 20oC - 40oC, the enzyme cannot gain enough kinetic energy from the thermal energy to move around and collide with the peroxide. ...read more.


This is because there are more faces exposed to the peroxide, if there are more faces exposed then this means there is more Catalase exposed to the peroxide. When more Catalase is exposed, it will be able to break down more Hydrogen Peroxide into Water and Oxygen, therefore the bigger the surface area, the more Oxygen given off from the reaction. Evaluation My experiment of surface area was a complete success as all my results were close together and similar. I had 1 anomalous result from my experiment, this was when the surface area of the chip was 12285.76 mm2, it was below the expected amount. This could have been because the chip had cooled down from 40oC and lost its kinetic energy, therefore this COULD have produced an anomalous result. On my graph I have used the line of best fit, I have tried to go through as many of the results as possible, I also tried to have equal amounts of points either side of the line. To improve my experiment and minimize the occurrence of anomalous results I could have used a water bath to keep the temperature of the experiment constant. This would prevent room temperature fluctuations which would lead to a change in the enzymes activity, (loss or gain of kinetic energy.) I also could have weighed the chips instead of cutting them into different sizes, cutting the chips is not very accurate, especially when I was cutting to lengths of 0.3125 cm. If I had weighed the chips its more likely that all the chips would have been the desired size. ...read more.

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