Finding the concentration of sodium carbonate.

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Finding the concentration of sodium carbonate:

Mass (Na2CO3 transferred to volumetric flask)

= [mass (weighing bottle) + mass (Na2CO3)]-[mass(weighing bottle after emptying)]

=15.24g – 12.59g

=2.65g

Molar mass (Na2CO3)

Na=23

C=12

O=16

2Na x 1C x 3O = molar mass

= (2 x 23) + 16 + (3 x 16)

=106

Number of mols (Na2CO3) = mass/molar mass

=2.65g/106

=0.025mol

Number of mols (Na2CO3) = concentration x volume

                                                              1000

0.025 mol. = conc. x 250cm3

                           1000

Concentration (Na2CO3)  = 0.1 mol.dm-3

Results

The first and last results are not included in the average since the first is only a rough titration so that later ones can be more accurate and the last is an anomalous result.

Therefore the average is:

(31.25+31.20+31.25) / 3 = 31.23cm3

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We can now number of moles of calcium carbonate using this equation:

Number of moles = concentration x volume

                                               1000

=0.1x25

   1000

=0.0025 mol.

The following reaction took place:

H2SO4(aq) + Na2CO3 (aq)                     Na2SO4 (aq) +H2O(l) + CO2 (g)

There is a 1:1 ratio of sulphuric acid to sodium carbonate.

Therefore the number of moles of H2SO4 will be the same as those of Na2CO3.

Number of ...

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