• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month
Page
1. 1
1
2. 2
2
3. 3
3
4. 4
4
5. 5
5
6. 6
6

# Finding the Empirical Formula for Magnesium Oxide

Extracts from this document...

Introduction

Finding the Empirical Formula for Magnesium Oxide The Results In order to work out the ratio for magnesium and oxygen, I will have to calculate the amount of magnesium and oxygen used. From these results, and knowing that the Ar for Magnesium is 24, and the Ar for Oxygen is 16, I can find the number of moles for Magnesium and Oxygen. Investigation 1: Magnesium = 36.08 - 36.04 = 0.04g Oxygen = 36.11 - 36.08 = 0.03g Magnesium Ar = 24 Oxygen Ar = 16 Investigation 2: Magnesium = 36.10 - 36.03 = 0.07g Oxygen = 36.14 - 36.10 = 0.04g Magnesium Ar = 24 Oxygen Ar = 16 To ensure that my final answer was as accurate as possible, I did not round any numbers until the end to get the most accurate final equation. Likewise for test 1, 3, and the average. Investigation 3: Magnesium = 36.10 - 36.03 = 0.07g Oxygen = 36.19 - 36.12 = 0.07g Magnesium Ar = 24 Oxygen Ar = 16 To ensure that my final answer was as accurate as possible, I did not round any decimals off until the end to maintain accuracy throughout the calculation. ...read more.

Middle

Oxygen is in the sixth group of the periodic table, and therefore has 6 electrons in it's outer shell, so needs to gain 2 electrons to achieve a full outer shell, as shown in the following diagram. So when the two of these elements react with each other, magnesium oxide is formed. In this, there are magnesium ions, which have a positive charge x 2, and negative oxide ions, (double negative charge). This shows that for each magnesium atom there is, one oxygen atom will react with it, as only one magnesium atom is needed to react with one oxygen atom for the outer shell of each to become full; two magnesium atoms are not necessary; the diagram clearly shows for each magnesium atom, one oxygen atom will react with it. The two electrons on the outer shell of the magnesium atom are transferred over to the gap of the outer shell of the oxygen atom, leaving both atoms with a full outer shell. Therefore, the formula for Magnesium Oxide is Mg O. ...read more.

Conclusion

To avoid this, the crucible with the magnesium oxide inside should have been reheated and then weighed again after the final weighing, until a constant mass could be found. It would be very difficult to perform this experiment accurately for tests 1, 2, and 3. Doing the experiment again, I would try and keep this part more accurate, but it is very difficult to maintain this level of accuracy. To further my experiment, perhaps I would experiment with different elements, e.g. use another element in group 2 of the periodic table with oxygen, to see if the formula would involve the same number of atoms, e.g. for Beryllium Oxide, I would expect the equation to be BeO, as magnesium and beryllium have a similar atom structure. I could also react magnesium with another element in group 6, such as sulphur. For this, I would expect the formula to be Mg S, because Sulphur has a similar atomic structure to oxygen, both holding 6 electrons in their outer orbital. Joanna Sedgwick 1 ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our GCSE Classifying Materials section.

## Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Related GCSE Classifying Materials essays

1. ## Experiment: To Determine the Empirical Formula of Magnesium Oxide.

However, the mole ratio of magnesium : oxygen was not exactly 1 : 1, but 1 : 1.1333.... The value was rounded down to 1. So, the empirical formula of magnesium oxide obtained from this experiment is not exactly MgO.

2. ## Periodic table

Every living thing has chromosomes - kangaroos: 6 pairs, fruit fly: 4 pairs, humans 23 pairs. Every cell in the human body will have 23 pairs of chromosomes or 46 pairs of chromatids. Sex chromosome - contains all the info.

1. ## Find out the theoretical yield of Magnesium Oxide, find the percentage yield of Magnesium ...

Because 24 is the relative atomic mass of Magnesium. So 2 Moles of Magnesium = 48g 2 Moles of MgO = 48 + 32 = 80g of MgO Because the relative atomic mass of oxygen is 32 and I added that to the relative atomic mass of Magnesium. 48g of Magnesium makes 80g of Magnesium Oxide.

2. ## The Structure of the Atom.

Q6 (HARD QUESTION). What physical properties might you expect to be different for different isotopes of the same element? Why 35.5? The two forms of chlorine are not present in equal quantities. In fact, in nature, only 25% of all chlorine is 37Cl, while 75% is 35Cl.

1. ## Rate of reaction of hydrochloric acid on magnesium.

produced was not appropriate because the scale wasn't accurate as there was no decimal places on the scale to measure the hydrogen produced. This problem was resolved by using a more accurate weighing scale to measure precisely how much gas was produced during the reaction.

2. ## Relationship between mass of MgO and its formula

128 u O } 48/128 = 0.375 u C / u O 8 atoms C @ 12 u each = 96 u C 16 atoms O @ 16 u each = 256 u O } 96/256 = 0.375 u C/ u O To clear this up we use John Dalton's theory, which supports the law of constant composition.

1. ## Finding the Formula of Magnesium Oxide

The magnesium could have over burnt and converted into ash, altering the mass of the magnesium oxide or could have burnt less. Conclusion: The primary purpose of this experiment was to obtain the empirical fomula of magnesium oxide. This objective was achieved by recording and analyzing appropriate data and coming up with the ratio of oxygen to magnesium.

2. ## Burning of magnesium metal

Substances can be classified according to how these atoms are assembled and are known as Classification of Matter: All matter falls into one of three categories: elements, compounds or mixtures. Furthermore, mixtures can be classified as homogeneous or inhomogeneous. The scheme looks something like the diagram below: This classification depends

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to