For my experiment I am going to attempt to observe the reaction between sodium thiosulphate and hydrochloric acid.

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Simon Law Dr Brazier GCSE Chemistry Coursework January 2003

SCIENCE COURSEWORK

Chemistry

For my experiment I am going to attempt to observe the reaction between sodium thiosulphate and hydrochloric acid.

What is the aim of my experiment?

The aim of my experiment is to measure the rates of reaction

What do we mean by the term ‘rate of reaction’?

The term rate of reaction means the amount of product and the time it reacts in. So the amount of product formed divided by the time taken.

In our experiment we cant find out the amount of sulphur that is created in the time. However the amount of sulphur made is constant so the rate is proportional to one over time.

I use the formula

                Rate= K                        K= constant

                         Time

This graph demonstrates the formula of one over time

Things that might affect the reaction?

Temperature will affect the reaction as the higher the temperature the more the particles will move around. Which in turn means the more the particles will collide with each other.

I am choosing to investigate the affect of concentration of sodium thiosulphate on the rate of the reaction. So from this I predict that increasing the concentration of sodium thiosulphate will cause the rate of reaction to increase. I predict increasing the concentration the quicker the reaction will be this is due to the collision theory, which states that for a reaction to take place particles have to collide, and with enough energy. The more particles more collisions will occur. By adding a more concentrated solution more particles are added which means more collisions and this is why I think the reaction will be quicker.

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W ill this affect the Surface Area?

The size of solid particles or surface area will affect the rate of reaction because if the reactant is a solid then you break it up in to smaller pieces which will increase its surface area. This means the particles around it in the solution will have more area to work on so there will be more useful collisions. If the sold particles is not broken up into smaller pieces then this would mean that the particles around it will have less area to work on and there will be collisions but ...

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