How does an increased surface area change the time taken for a mass to fall?

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How does an increased surface area change the time taken for a mass to fall?

Aim

The aim of this investigation is to find out how the change in surface area changes the time for a mass to fall at certain heights.

To do this, I am going to use a large cup cake as a mass with a large surface area and a small cup to be the mass with a small surface area. They are going to both be the same mass to make this a fair test. The cup cakes are dropped at given heights and the time period will be the tine taken for it to reach the ground from when it starts to fall. With this, we can look at the times to see what affects the change in surface area has with a given mass.

 In my preliminary experiment, I am going to determine what mass is going to used, the minimum and maximum heights at which the cup cakes are going to be dropped for both and create a graph of the range of results to approximately know what range of results I should come up with when I am actually doing the experiment. The graph will determine what generally happens whilst the cup cakes fall and will show the affects that the different surface area has on them.

Preliminary Work - showing which variables we can study.

From this preliminary experiment, I have determined the minimum and maximum height at which the cup cakes are going to be dropped from and the mass of both cup cakes. It seems from these results; the higher the cup cakes are dropped at, the longer the time for it to reach the ground. The results seem reasonable at the mass we did this experiment at which was 0.33g. With this mass, it seems that it did not drop too fast or too slow. From looking at my preliminary results, I have come up with my final variables:

Maximum height = 260.00cm

Minimum height =50.00cm

Mass of cup cake = 0.33g (for both cup cakes to make fair test)

Prediction

My prediction is that the larger the surface area is, the longer the time will be taken for the mass to reach the ground. Also the object will accelerate until it reaches a constant velocity, where it will drop at approximately (with experimental error) the same velocity but this constant velocity will change for both cup cakes due to the its surface area. The larger cup cake with the larger surface area will drop with a slower constant velocity so therefore it will reach the floor in longer time periods. The small cup cake with the smaller surface area will reach the floor in a shorter time due to its surface area being smaller, therefore having a larger constant velocity. On the graph I will expect a little curve showing the acceleration of both cup cakes but will quickly end up in a straight line until it reaches the bottom. The gradient of the smaller cup cake will be steeper than the larger one due to its greater constant velocity. The scientific explanation is explained below.

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Background theory

To explain what happens, we must use scientific evidence to prove this. First we must know about Newton’s third law:

Resultant force = Mass x Acceleration (f = m.a)  

In this experiment, mass is kept constant so it cannot affect the resultant force. This means the only variable to change the resultant force is acceleration. Therefore for the resultant force to increase, the acceleration of the cup cakes must increase. When the cup cake starts to fall at the very start, its resistance is 0.00N. The smaller cup cake will have a higher ...

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