How does the amount of Copper Carbonate effect the amount of Copper Oxide?

X is the amount of Copper Carbonate in grams.

80

X = 124 x X

Eg

1 gram = 80

24 x 1= 0.64g

2 grams = 80

24 x 2= 1.29g

3 grams = 80

24 x 3= 1.92g ECT

This is worked out by taking the atomic mass of the starting product, which is Copper Carbonate, with an atomic mass of 124.This is worked out by adding the atomic mass of all the elements in Copper Carbonate. These are Copper (63), Carbon (12) and 3 atoms of oxygen ( 3x 16 ). Then take the atomic mass of the product you want, which is copper oxide with an atomic mass of 80. Then divide the atomic mass of your starting product by the atomic mass of the product you want. Then times your answer by how many grams of copper carbonate you started off with. That gives you a rough idea about how much copper oxide is produced.

Method

First we will measure out the amount of copper carbonate. Then add it to a test tube and heat it until all the copper carbonate has turned black. Then measure what is left. We will repeat this 3 times for each weight and then take the average. I will then record my results into a table.

Fair testing

To help make sure that it is a fair test we will repeat the experiment 3 times and take the average. I will use different test tubes every time and I will weigh out the copper carbonate correctly. I will use the same Bunsen Burner on the exact same heat.

Jamie Moir 11F 12/04/02

Results

Amount of Copper Carbonate

Prediction

Result 1

Result 2

Result 3

Average

g

.64g

2g

.29g

3g

.92g

4g

2.56g

5g

Evaluation