I am going to examine the resistance of a length of wire.

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W. Vaughan                27/04/2007

PHYSICS COURSEWORK

INVESTIGATING THE RESISTANCE OF A WIRE

INTRODUCTION

I am going to examine the resistance of a length of wire. There are a number of variables which I think will alter the behaviour of the resistance. These are heat, length, diameter, atmospheric pressure and height. There are two that are feasible to investigate in classrooms which are length and diameter. From these two I have decided to choose length as there seems to be a wider range of variables compared to the diameter of a wire. To check that this variable showed significant variation I carried out a preliminary experiment to verify this. From this preliminary experiment I observed that there definitely seemed a correlation between the length of the wire and the resistance achieved. I will define the quantities in Ω (ohms).

HYPOTHESIS

I predict that if we double the length of the wire the resistance will double therefore showing a direct correlation between the two. I compiled these results from the quick preliminary experiment.

EXPLANATION

Resistance is the property that transforms electrical energy into heat energy. All the atoms in conductors have free electrons. When there is a potential difference through the metal all the electrons line up creating an electrical current. Resistance is encountered when these electrons collide with other fixed particles in the material. The bigger the resistance the larger the force is needed to pump the same amount of current around the circuit. The formula to work out resistance is:

                

                Resistance [Ω (ohms)]        =        Volts [V]        /        Amperes [I]

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This is called Ohm’s Law. Therefore when the length of wire increases it will have to collide with more particles meaning a bigger currant is needed and the wire will heat up. There is also another formula which I did not know about until I began investigating resistance:

“Resistance, in ohms (R) is also equal to the resistivity of the wire, in ohm-meters (ñ) multiplied by the length, in meters (l) divided by the cross sectional area, in square meters (A).”1

The cross sectional area of the wire is the same therefore we can see from this formula that ...

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