I am trying to find out how the concentration of hydrogen peroxidesolution (substrate) affects the amount of oxygen produced. I will use different concentrations of substrate, with an enzyme (catalase) from a potato. I will measure the volume of ...

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Frances Duffy 10H1 Biology Coursework

The Effect of Substrate Concentration

On an Enzyme Catalysed Reaction.

PLAN

Aim:

I am trying to find out how the concentration of hydrogen peroxide solution (substrate) affects the amount of oxygen produced. I will use different concentrations of substrate, with an enzyme (catalase) from a potato. I will measure the volume of oxygen produced when the catalase breaks down the hydrogen peroxide solution. I am also trying to find out how the concentration of hydrogen peroxide solution will affect the rate of reaction of the oxygen produced. The enzyme, catalase, produces the reaction below. It shows us that when catalase breaks down the substrate, water and oxygen are produced.

                   

                Hydrogen Peroxide                                Water + Oxygen

                                                     CATALASE

                         2H  O                                             2H  O + O  

Prediction:

I predict that the higher the concentration of hydrogen peroxide there is, more oxygen will be produced in the allotted time. When there is a 100% concentration of hydrogen peroxide, in my case 25ml, I think the most oxygen will be produced. From then on, as the concentration gets weaker, I think less oxygen will be produced and at a slower rate. I would expect 100% to react quickest because it has the most hydrogen peroxide molecules in it. With more of these molecules inside the solution, it is more likely that reactions will take place. This means that a reaction is more likely to take place in a shorter time, making the rate of reaction quicker.

After 100% producing the most oxygen, I then expect it to be 60%, then 40%, and then 20%. An increase in the substrate concentration will produce a corresponding increase in the rate of reaction. Therefore, when the concentration is doubled, as in from 20% to 40%, I also expect the amount of oxygen produced in the reactions to double.

I think this because if the solution of hydrogen peroxide is stronger, the catalyse in the potato will have more hydrogen peroxide molecules to break down. If there is a weaker concentration of hydrogen peroxide solution, then there will be less hydrogen peroxide molecules for the enzyme to break down, and less oxygen will be produced in the allotted time.

Enzymes are biological catalysts, which can speed up chemical reactions without being changed itself. Each enzyme molecule has an indentation, which is different for every enzyme. The dents are called active sites. Catalase has an active site specially made to fit hydrogen peroxide molecules, and the site is exactly the right shape and size to fit the hydrogen peroxide molecule in and break it down. The molecule enters the active site, and the enzyme breaks it down into another substance, in our case water and oxygen. The diagrams below explain how enzymes work:

  Hydrogen Peroxide Molecule                    

                                                  Active Site

                            Enzyme (catalase) Molecule

  1. Each enzyme has an active site. This active site is exactly the right shape and size to fit the hydrogen peroxide molecule.
  2. The substrate molecule, hydrogen peroxide, slots easily into the active site of the enzyme.
  3. The enzyme has successfully broken down the hydrogen peroxide molecule into water and oxygen.
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Fair Test:

To make the experiment a fair test, I will make the hydrogen peroxide the independent variable. I will do this by changing its concentration throughout the experiment. I have to make this the independent variable because if it was the same all the way through, the amount of oxygen produced would stay the same. My dependent variable will be the amount of oxygen that is produced, and I will measure the volume of this each time.

I will also make my experiment a fair test by controlling variables to stay the same throughout the experiment, such ...

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