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I will be carrying out an experiment where I will be testing how a difference in mass can affect the rate at which a helicopter can fall.

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I will be carrying out an experiment where I will be testing how a difference in mass can affect the rate at which a helicopter can fall. In order to measure the time it takes for the helicopter to fall, I will be using a stopwatch. However, an alternative to using a stopwatch to work out the time would be to use the formula S = UT + 0.5AT2 where S = distance, U = initial velocity and A = regular acceleration, in this case 9.8m/s-2 , but this does not take into consideration the changing mass of the helicopter, and therefore cannot be used. This will allow me to work out the time that it takes the helicopter to fall. Variables: * Surface area * Mass * Air Density * Aerodynamics * Initial Velocity * Height Hypothesis: In this investigation, as the mass of the helicopter is increased, the faster it will fall. This is because with more mass gravity gets stronger and pulls the object down. With less mass it will give the object less pull so it will stay in the air longer. ...read more.


Once an object has reached this speed, it will continue to fall at a constant rate until it hits the ground. This is Newton's first law of motion. If an object starts its descent at a higher speed, it will reach terminal velocity faster and therefore it will descend faster. When the drag and the Drag (R) weight become equal, we say the object has reached Terminal Velocity. R = W (Terminal Velocity) Weight (W) The Height that the object falls from will alter the time it takes to descend. The greater height the object starts from, the longer it will take to fall back down to earth. If the object only falls a short distance, it also might not have had time to reach its terminal velocity. For this experiment, I have chosen to alter the mass that the helicopter falls with. I have chosen this variable because it is unlikely to produce any anomalous results. The results would also be straightforward to collect. Safety during Investigation: This investigation does not involve the use of anything dangerous. Care will be taken when taking results. ...read more.


By looking at the graph that shows Mass vs. Time of descent, we can clearly see that as the mass went up, the time the helicopter took to reach the ground was decreased. By observing the results, we can work out many other things about the helicopter, such as its acceleration: Change in velocity (m/s) divided by Time taken in seconds. For the 0.9 gram helicopter: Change in velocity is speed - starting speed: 0.78490566 - 0 The change in velocity is 0.78490566 The time taken is 3.3125 The acceleration is 0.2369 meters per second. The formula for terminal velocity is square root of ( 2W/Cd r A). W is weight, Cd is drag coefficient and r is air resistance and a is frontal area. We were not given values for all these variables so we got measurements for terminal velocity by using the pictures we took and observing when the helicopter hit terminal velocity, then we calculated the sped but the calculation, Height that terminal velocity is reached, divided by the time it took for the helicopter to hit the ground from that point. Evaluation: Our experiment is not entirely accurate, due to the fact that we were unable to accurately measure when the helicopter reached terminal velocity. The results we took were fairly accurate, as there are no anomalies present. ...read more.

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