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Investigate how the thickness of the wire affects the resistance of the wire. I am aware that there are other things that affect the resistance.

Extracts from this document...

Introduction

Alexandra    malolepsza                             Physics Coursework            Johnathon Lisseman

Science Investigation:  I will investigate how the thickness of the wire affects the resistance of the wire. I am aware that there are other things that affect the resistance. Such as:

• Length of wire
• Temperature
• Type of wire
• Thickness

I have decided to investigate thickness.

Equipment:

• Ammeter
• Voltmeter
• Power Pack
• Leads
• 3 thickness of wire
• 3 Different types of wire

Method:

1. Set up the equipment in the following way:

A

V

1. Choose a thickness of wire and connect it to the circuit.
2. Turn on the power pack and measure the current and the voltage. Record both results in a table. Repeat this 3 times for each thickness of wire, so that it will be a fair test.
3. Now work out the resistance for each, by dividing the voltage by the current, using the formula: R = V    R= Resistance V= Voltage

I =current                                I

1. Record the resistance in the table.
1. Draw a scatter diagram to represent the results.

FAIR TEST FOR VALIDITY:

Things that I will keep the same:

• Power pack
• Ammeter
• Voltmeter
• Leads
• Temperature

...read more.

Middle

 Length (cm) Voltage (V) Current (A) Resistance(Ω) 20 cm 50 cm 100 cm

Prediction:

An atom consists of a nucleus and orbiting electrons. These electrons can create a flow of current, so the more free electrons there are, the more conducting capability that material has.

The wider the wire, the more space in the net for the charged electrons to get through without colliding with the net, and therefore decreasing the resistance. It is like letting a lot of water out of a small hole; it would go slowly, whereas with a bigger hole it flows out faster.

So, wires with a wider diameter have more free electrons, because the cross-section surface area is larger in proportion to the length, so the wider the wires are, the less reactive they would be. Resistance is proportional to the cross-section of the wire given that the length and the material should be the same.

Constantan:

 SWG 0.2 (V) 0.4(V) 0.6(V) 1 (V) 26 0,66(A) 1,39(A) 2,03(A) 3,46(A) 30 0,33(A) 0,64(A) 0,92(A) 1,52(A) 32 0,22(A) 0,49(A) 0,78(A) 1,41(A)

Copper:

 SWG 0,2(V) 0.4(V) 0.6(V) 1 (V) 26 3,66(A) 7,50(A) 13,65(A) 16,34(A) 30 * 32 3,42(A) 5,48(A) 6,70(A) 8,23(A)

*No wire available.

Nichrone:

 SWG 0,2(V) 0.4(V) 0.6(V) 1 (V) 26 0,58 (A) 0,92(A) 1,21(A) 1,85(A) 30 0,27(A) 0,43(A) 0,59(A) 0,89(A) 32 0,23(A) 0,35(A) 0,48(A) 0,71(A)
...read more.

Conclusion

Analysing my graphs:

From my graphs we can see that in all three wires, the thicker the wire the smaller the resistance. There doesn’t seem to be any anonymous results.

In all my graphs all the points have a positive colleration, which supports my prediction. The thicker the wire the lower the resistance. This is because in a thicker wire there are more pathways for the electrons to pass thorough so they don’t bounce off of eachother so much as they would in a thin wire.

From my graph we can also see that voltage is directly proportional to the current, which means the resistance is as well. So as the voltage goes up so does the current. This again supports my prediction. I was able to draw lines of best fit, because all the points had a strong positive colleration.  None of the point lay far away from the line of best fit. Most are either on the line or very close to it.

...read more.

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