Investigate the effect of temperature on the activity of catalase (from potato).

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Aim: Investigate the effect of temperature on the activity of catalase (from potato).

Introduction: Enzymes are biological catalysts. They speed up metabolic reactions in the body but remain chemically unchanged themselves. Enzymes contain an active site. This is a region, normally a depression or cleft, to which another molecule may bind. This molecule is known as the substrate, and is usually specific to the active site of the particular enzyme, which breaks it down. Substrates will not usually fit into any other active sites other than that of the enzyme it is specified to. This can be explained as a lock and key model, where the lock and key are specific to each other, only, that there are many of the same kinds of lock and key when it come to the enzymes.

Just as lock and keys have three-dimensional shapes, proteins are also three-dimensional. Usually, there is only one active site on an enzyme; however there can be more. Some energy releasing reactions in cells produce hydrogen peroxide. This is acidic, and can thus, kill cells. Normally, hydrogen peroxide decomposes to form hydrogen and oxygen:

2H2O2 2H2O + O2

However, this process is very lengthy. There is an enzyme known as catalase in cells which dramatically increases the rate of decomposition of hydrogen peroxide.

catalase

2H2O2 2H2O + O2

This type of reaction where a molecule is broken down into smaller pieces is known as a catabolic reaction.

In order to investigate the effect of temperature on the activity of catalase, I will record the amount of oxygen released when hydrogen peroxide is broken down.

Variables: There are quite a few variables which can alter the rate of reaction, and need to be kept constant. They are as follows:

a) PH: at too high PH, the enzyme is denatured due to the loss of H+ ions. The same applies for too low a PH level, where too many H+ ions would attach to the negative regions of the enzyme, changes its shape and causing it to denature.

b) Concentration of enzyme: The higher the concentration, the higher the rate of reaction will be. With a larger number of catalase molecules, the chance of successful collisions between enzyme and substrate will be increased. In order to keep this constant, I will make sure I use the same volume of tissue (potato) containing catalase each time I conduct the experiment.

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c) Surface area: The previous also applies to this.

d) Mass of tissue: Here it needs to be taken into account that different potatoes will not give the same mass, even if equally sized pieces are cut. Different potatoes will not have exactly the same water and catalase content.

Arefin Khan

The mass will be kept constant in the same way as surface area and concentration of enzyme.

Prediction: The higher the temperature, the higher the rate of reaction up to a certain point. This is due to the fact that the particles gain kinetic energy and subsequently move around ...

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