Investigate the factors that effect the current flowing during the electrolysis of an aqueous solution of sodium chloride.

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CHEMISTRY INVESTIGATION

PLANNING

AIM

The aim of this experiment is to investigate the factors that effect the current flowing during the electrolysis of an aqueous solution of sodium chloride. In this experiment, I will keep the voltage, the volume of water, the mass of salt, temperature, and the distant between electrodes constant, while varying length of electrode in the water.

VARIABLES

       In this experiment, I will only use one variable, although there are others to consider to ensure a fair test. As, if more than one factor is varied during the experiment, the results will not be reliable. These variables are:

  • The length of the electrode in the water
  • Temperature
  • Mass of sodium chloride
  • Volume of water
  • Distance between electrodes
  • Voltage

During this experiment, I have chosen to vary the mass of sodium chloride in the solution. I will keep all the other factors constant. I will achieve this by using :

  • A ruler to measure the length of electrode that is in the water.
  • A thermometer to check the temperature.
  • A beaker with clear and accurate measurements on it to keep the volume of water constant.
  • I will use an electrode holder that will hold the electrodes a set distance apart.
  • I will use the same power pack throughout the experiment, as not all power packs give out the same voltage.

     

PREDICTION

       

        My hypothesis is that the more sodium chloride dissolved in the water the higher the current will increase. In a dilute solution, there are less sodium chloride particles. This means there is less chance of a sodium chloride particle hitting an electrode as compared with solution of a higher concentration. In a concentrated solution, there are more sodium chloride particles, therefore there is a greater chance of a particle hitting an electrode.

       I also predict that chlorine, hydrogen and sodium hydroxide solution will be produced as a product of this experiment.

       This is because chloride ions are negatively charged and therefore are attracted to the positive anode. This electrode process produces chlorine gas.

Chloride ions →chlorine molecules + electrons

2Cl¯(aq.)       →         Cl (g)             + 2e

As the chloride ions are no longer present in the solution, it leaves a high concentration of sodium ions at the anode. While at the cathode the positive hydrogen ions are being attracted. This results in hydrogen gas being produced.

Hydrogen ions + electrons → hydrogen molecules

2H   (aq.)         +       2e      → H  (g)

This means that there is now a high concentration of hydroxide ions, around the cathode, and sodium ions around the anode. As sodium ions are positive and hydroxide ions are negative, they attract to form sodium hydroxide solution.

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EQUIPMENT

  In this experiment, I will use:

  • an electrode holder
  •  a power pack
  •  an ammeter
  •  two carbon electrodes
  • a glass rod
  • a set of electronic scales
  • a 500-CL beaker
  • two crocodile clips
  • a thermometer
  • two splints

DIAGRAM

METHOD

  • I will set up my equipment as the diagram shows.
  • I will pour 500-cl of distilled water into a 500-cl beaker.
  • I will weigh 5 grams of sodium chloride on a set of scales.
  • I will ...

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