Investigating factors affecting the resistance of a metal wire.

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Rhodri Williams        11X        Science Group C

 Investigating into factors affecting the resistance of a metal wire

Plan

Introduction

  Metals can be described as regular rows and columns of positive ions surrounded by a sea of electrons. Each atom in a piece of metal loses one, two or three electrons, which can then move around in the metal:

                                

                                

                                Positive ion

                                Electron

Metals conduct because these electrons can be pushed along by a power supply. Resistance comes about because the electrons in a wire continually collide with the stationary ions. So if there is a high resistance, electrons collide with the ions more, so less pass each point each second, so the current goes down.

  A longer wire has more atoms, so more ions, while offering no increase in cross sectional area. Because of this, there are more ions with which the electrons can collide, so there is a higher resistance.

  Different materials will have different resistances, as metals have different distances between atoms, different sized atoms, and different numbers of electrons released. A large distance between atoms means that electrons can get past more easily, so a lower resistance. In a metal with large atoms, there would be a greater chance of an electron hitting one, so a higher resistance than a metal with small atoms. The more electrons released, the more that can pass each point every second, so the lower the resistance.

  An increase in temperature would cause the atoms to vibrate more, so the electrons would have a higher chance of colliding with an ion, so the resistance would increase.

 Increasing the cross section area would decrease resistance. This is because the metal is many more atoms thick, so more electrons are released. Because of this, more atoms pass each point every second, so there is a lower resistance.

The factor I have chosen to investigate

  I have chosen to investigate the result of increasing the cross section area of the wire.

Control of variables

  Temperature, wire length and wire material must be kept the same to ensure a fair test, for reasons described in the introduction.

Prediction

  I predict that the resistance will be inversely proportional to the wire's cross section area. This means that if the cross section area doubles, the resistance should halve. This is because at each cross section of the electric wire, there will be more electrons, so more electrons will pass each point every second.

  Here, there are few electrons across the cross section of the wire.                

  Here, the wire twice as thick, so has twice as many electrons across the cross section. So, twice as many electrons will pass every point each second, so the resistance will be half that of the thinner wire.

 

 

  The graph of results should look similar to this one, if the resistance is inversely proportional to the cross sectional area:

  The points should line up, and the line of best fit should go through the origin.

Preliminary experiments

  •   Using a voltmeter, increasing the voltage to see if the temperature of the wire is affected, and so finding a voltage small enough that the temperature of the thickest and thinnest wires does not change. If there is no temperature change on the thickest and thinnest wires, it can safely be said that there won't be a change with the other wires.
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  Results showed that the thickest wire, of 20 SWG, got quite hot when the voltage reached 1 V. A safe voltage is 0.300 V, as the wire does not heat up noticeably. The thinnest wire, of 38 SWG, didn't increase in temperature noticeably at any voltage tried, but if the voltage is kept under 2 V, the voltmeter can be changed to a more accurate measurement setting, which goes to three decimal places. This is also useful because with a low voltage, there is also a low current, so a milliammeter can be used instead of an ammeter, to ...

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