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Investigating how changing the concentration effects the rate of the reaction between hydrogen peroxide and catalase from a potato.

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Investigating how changing the concentration effects the rate of the reaction between hydrogen peroxide and catalase from a potato Planning Introduction The enzyme catalase breaks down hydrogen peroxide into water and oxygen. Hydrogen peroxide is a highly active chemical, often used in bleach or for cleaning minor wounds. It is also formed continually as a byproduct of chemical reactions in a living cell. It is toxic and if the cells did not immediately break it down it would destroy them. Hence the importance of the enzyme. It is in fact the fastest enzymes known. The enzyme is able to speed up the decomposition of Hydrogen peroxide because the shape of its active site matches the shape of the Hydrogen peroxide molecule. This type of reaction where a molecule is broken down into smaller pieces is called an Anabolic Reaction. Catalase Hydrogen Peroxide Water + Oxygen 2H2O2 2H2O + O2 In this investigation I will be able to watch the action of catalase in a test tube and compare it with an inorganic catalyst that causes the same reaction. ...read more.


Firstly I will be cutting my potato in half and then cutting 6 cubes of 1cm� with my scalpel on a cutting tile. I shall leave these pieces on a petri dish in distilled water to stop the pieces becoming dry. 2) Then I will take my first test tube which will be prepared with 0M (50ml distilled water). I will then leave this test in a water bath at 20�C so that the content of the test tube is at the right temperature. I have chosen 20�C because this is the temperature where the enzyme catalase is at its optimum. At this temperature the enzyme and the substrate are reacting the quickest they can. As the piece of potato is put into the tube I shall straight away put a cork on top which will have a delivery tube coming out of the test tube which is connected to a syringe, the syringe is used to collect the oxygen produced from the reaction. 3) I shall be leaving the reaction to occur for 90 seconds and I shall then disconnect the delivery tube from the test tube and then seal the ends, letting the remaining oxygen enter the syringe. ...read more.


Prediction I predict that as the substrate concentration increases, the rate of reaction will go up at a directionally proportional rate until the solution becomes saturated with the substrate Hydrogen Peroxide. When this saturation point is reached, then adding extra substrate will make no difference. The rate steadily increases when more substrate is added because more of the active sites of the enzyme are being used which results in more reactions so the amount of Oxygen released in a given time is higher. Once the amount of substrate molecules added exceeds the number of active sites available then the rate of reaction will no longer go up. This is due to the maximum number of reactions being done at once, so any extra substrate molecules have to wait until some of the active sites become available. Table of Results 1 2 3 4 5 Concentration Amount of oxygen produced (cm�) Amount of oxygen produced (cm�) Amount of oxygen produced (cm�) Amount of oxygen produced (cm�) Amount of oxygen produced (cm�) 0 0.2 0.4 0.6 0.8 1 Concentration (M) Average amount of oxygen produced (cm�) Rate of reaction Simon Ellis L6Er Biology Coursework ...read more.

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