Investigating how the concentration of hydrochloric acid affects the rate of reaction with Calcium Carbonate.

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ST        Susie Willmott (U10)

Investigating how the concentration of hydrochloric acid affects the rate of reaction with Calcium Carbonate.

Aim

Calcium Carbonate reacts with dilute hydrochloric acid to produce carbon dioxide.  The aim of this investigation is to find out how the concentration of hydrochloric acid affects the rate of reaction with calcium carbonate.

        

        In my experiment, I will use an overall volume of 50 cm³ of 2moles of dilute hydrochloric acid and keep that constant throughout the entire experiment.  Another independent variable in my experiment is the one-gram of calcium carbonate; I will also keep the surface area of the calcium carbonate the same.

        

        In each experiment I will vary the concentration of acid I use, ranging from 50 cm³ of acid and no water, to 12.5 cm³ of acid and 37.5 cm³ of water.  The equation for the reaction between Calcium carbonate, hydrochloric acid and water is:

CaCO³ + 2HCl → CaCl² + H²O + CO²

Background information

My experiment is based on the collision theory.    This means that the particles in the solution continuously move around, this means that sometimes the particles collide.  If the collision has enough energy a reaction takes place, but if the collision does not have enough energy, no reaction occurs and the particles bounce away from each other.  In a successful collision, you need energy to break the bonds and then it would release energy as new bonds are formed.

        

The more successful collisions that happen, the more products from the experiment are produced.  This also means that the more successful collisions that happen the higher the rate of reaction.  However, the less successful collisions, the lower the rate of reaction and therefore fewer products are produced.

        

So, ideally, in my experiment, the higher the concentration of acid the higher the rate of reaction and the more carbon dioxide is produced.

Preliminary Work

The key factors that will affect my experiment are the concentration of acid, the size and therefore the surface area of the calcium carbonate and the number of moles of hydrochloric acid.  

I will vary the concentration of acid and keep to one size of calcium carbonate and only use 2 m of hydrochloric acid.  This way I can observe the different affects different concentrations of hydrochloric acid have on the calcium carbonate and the rate of reaction.

        

I will measure the amount of carbon dioxide that is given off by the calcium carbonate and hydrochloric acid.  I will do this by recording what level the water is at in the measuring cylinder every 10 seconds.

        

Hydrochloric acid is an irritant and I will therefore handle it with care and always wear safety glasses when performing the experiments.

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Apparatus

*Safety glasses*

Balance

Medium sized Calcium Carbonate

2 m of hydrochloric acid

Flask (with a bung and a glass tube)

Bowl full of water

100 cm³ measuring cylinder

50 cm³ measuring cylinder

Stand, Clamp and Boss

Stop Watch

Supply of water

To begin my investigation, I will put on my safety glasses for safety and use a balance to measure 1 gram of medium sized calcium carbonate.  I will need a flask with a bung so the released carbon dioxide does not disperse into the air instead of going down the tube into the 100 ...

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