Investigating how the rate of hydrolysis of halogenoalkanes varies.

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Investigating how the rate of hydrolysis of halogenoalkanes varies.

Aim

To investigate how the rate of hydrolysis of a halogenoalkane varies.

Hypothesis

-iodobutane will produce a yellow precipitate of silver iodide quicker because it has the lowest bond enthalpy and 1-bromobutane will produce a white precipitate before 1-chlorobutane because the strength of the bond decreases.

I also think that it becomes easier for the bond between the carbon atom and the halogen to break.

Introduction

A halogenoalkanes are compounds made up of Carbon, Hydrogen and halogen atoms such as Fluorine, F, Chorine, Cl, Bromine, Br and Iodine I. Their general formula is CnH2n+1X. They are named by prefixing the name of the alkane with fluro, chloro, bromo and iodo respectively. So CFCs are Chloro Fluoro Carbons etc
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Because Halogens are Electronegative attaching one to a carbon atom would create a Polar Covalent Bond. Therefore the carbon atom provides the C + atom which can be attracted by a nucleophiles.

Halogenoalkanes are classified according to their structures, primary, secondary and tertiary.

In a primary halogenoalkane the halogen atom is covalently bonded to a carbon atom, which in turn has a covalent bonded to just one other carbon atom.

In a secondary halogenoalkane the halogen atom is covalently bonded to a carbon atom, which in turn has a covalent bonded to just two ...

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