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Investigating the effect of Temperature upon the Enzyme Catalase

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Investigating the effect of Temperature upon the Enzyme Catalase Introduction: Living cells continually carry out chemical reactions and produce hydrogen peroxide. It is a toxic substance which would destroy the cell if it's not immediately broken down. This breakdown is carried out by the enzyme CATALASE, which is produced in Living cells. Catalase breaks down the hydrogen peroxide into water and oxygen making it harmless to the cell. Hydrogen Catalase Peroxide Water + Oxygen 2H2O2 2H2O + O2 Therefore Catalase is the catalyst. Hydrogen peroxide is the substrate Catalase is the fastest enzyme known when it comes into contact with H2O2, Bubbles (frothing) show rapid production of oxygen. Aim: To study the action of Catalase upon potato at different temperatures. I plan to assess the reaction by measuring the volume of oxygen produced in three minutes. Method: 1. Grate 5g potato. This will increase the surface area and also break open the cells to release the enzyme Catalase. 2. Put the tissue into a conical flask. 3. ...read more.


80 C - Placing the tissue + H2O2 in a water bath Apparatus: * 5g potato * Knife * Grater * White tile * Comical flask * Delivery tube + bung with 2 holes * 100cm3 measuring cylinder * Glass tank * Stop clock * Crushed ice * Water bath * Thermometers * Electronic balance Fair test: To make it a fair test I had to...... 1. Make sure the potato was from the same batch. 2. Same amount of potato is used 3. Same volume of hydrogen peroxide used 4. Time taken for reaction between potato and hydrogen peroxide 5. Time taken to leave reactants at each temperature before mixing them Prediction: I predict that this experiment will be a success. I think that the most successful temperature was between 40 c and 50 c. If I used liver instead of potato, it would be more effective, liver has more enzymes, which reacts better with hydrogen peroxide. ...read more.


At the higher temperature (60 and 80 degrees). The volume of oxygen produced declines, this is because enzyme molecules begin to denature. This means that the active site of the molecules is put out of shape therefore cant react with hydrogen peroxide and no oxygen is given off. Evaluation: I found that my results had anomalies in experiment 1 at temperature 50 c3 and in experiment 2 at temperature 12 c3. This may have been due to errors in the method/procedure. For instance I left the catalyst and hydrogen peroxide at each temperature for 5 minutes to used to the temperature. Other reasons for anomalies could be because I measured the enzyme incorrectly or the potato was to old by the second experiment. There were some problems with carrying out the experiment, they were that the baths were unreliable, it was hard to get them to the correct temperature. If I could do this experiment again I would improve it by doing the measurements correctly and following the procedure. ...read more.

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