Investigating the effect on concentration upon the rate of a reaction

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INVESTIGATING THE EFFECT OF CONCENTRATION UPON THE RATE OF A REACTION

SAM SCHOFIELD

11G

PLANNING


Practice experiment

Due to the nature of the coursework, it was deemed necessary to perform a practice experiment, so it was possible to investigate the results and understand the experiment in rough terms prior to the actual coursework investigation.

This also aided in the planning of the work, as background information was provided, resulting in a more precise and accurate set of results in the final tasks.

Investigating The Effect Of Concentration Upon

The Rate Of A Reaction

PLANNING

We are performing an investigation to find the effect that changing the concentration of the solution has upon the time that it takes for two chemicals to react together.

1) Sodium thiosulphate solution reacts with acid (we chose to use hydrochloric) to form sulphur. This is the experiment we are going to perform.

2) We will time how long it takes for enough sulphur to form, for us not to be able to see the cross that we will draw on a piece of paper.

3) We will take readings of different concentrations of sodium thiosulphate.

4) We will take a reading of each solution three times, and find the average.

5) The results should show us that the solution will form sulphur quickest when the solution is more concentrated.

We will perform this experiment in the safest and most properly controlled manner, both with goggles and also we will make the experiment safe, by performing the following acts:

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  •  Using the same but cleaned out conical flask, so we use the correct amount of solution and so the correct concentration is used.
  • Measuring the solution to the amount of 60 centimetres cubed each time.
  • By making sure that we use the same “X” each time we take a reading, so we do not get different results each time. If we used a smaller cross for instance, it would take less time to disappear.
  • By taking three readings if necessary so we find the average. (Add all three results together and divide that number by 3 to ...

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