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Investigating the factors that affect the action of catalase (enzyme) on hydrogen peroxide.

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Introduction

Biology Coursework Investigating the factors that affect the action of catalase (enzyme) on hydrogen peroxide Daniel victory 11BY Analysing From both my tables of results and my graphs we can see that my results match my predictions that the larger the surface area of the potato, the faster the rate of reaction will be and that as more time passed the rate of reaction decreased. So I can say that the surface area of the potato is proportional to rate of reaction and that time is inversely proportional to rate of reaction. I think that as the surface area of the potato increased, the rate of reaction also increased because there was more catalase molecules involved in the reaction and the hydrogen peroxide molecules also had more area to react with the catalase and therefore there were more collisions between molecules and therefore the 'lock and key' mechanisms were taking place faster. ...read more.

Middle

Eventually, no matter what surface area of potato is used, considering it is not a ridiculously small surface area, there will always be the same number of bubbles produced by the reaction seeing as the catalase will never run out and it will therefore decompose all of the hydrogen peroxide, the only difference being that with potatoes with smaller surface areas the rate of reaction will be much slower than that of potatoes with larger surface areas. My graph of time against number of bubbles per minute also gave me curves which tells me that after a certain time no bubbles will be produced anymore because all of the hydrogen peroxide will have been decomposed so there will be no more reactions. I think that the larger the length and surface area of the potato, the faster its reaction would get to the point where no more bubbles would be produced seeing as there would be more catalase molecules involved in the reaction so there will be more collisions with the hydrogen peroxide molecules and therefore the 'lock and key' mechanisms would take place faster. ...read more.

Conclusion

No matter what amount or concentration of hydrogen peroxide would be used or what surface area of potato, the catalase would always remain the same throughout the experiment and would be unchanged at the end of it. From my experiment I can say that I have found out the following things: * The enzyme catalase makes hydrogen peroxide decompose into water and oxygen faster than it would on its own. * The larger the surface area of the catalase, the faster the hydrogen peroxide decomposes, so more oxygen is produced in a certain amount of time. * The longer the experiment goes on for, the hydrogen peroxide decomposes slower, so the production of oxygen starts slowing down. * No matter what the surface area of the catalase, the same amount of oxygen will always be produced, considering that the amount of hydrogen peroxide is kept constant, just over a different amount of time. ...read more.

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