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Investigation of Resistance in a Nichrome 32 Wire

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David Privett 10CK Science Coursework: Investigation of Resistance in a Nichrome 32 Wire Introduction: In this project I will be investigating how the length of Nichrome wire will affect the resistance. All length, cross section area, temperature and type of material are the factors that affect resistance. I will be keeping these variables constant besides length. To carry out this experiment I will set up a simple circuit and carry out a series of trials measuring voltage and current using different lengths of wire. Prediction: I predict that when the length of the Nichrome 32 wire is increased the resistance will also increase equally. The resistance increases as the length increases because the electrons that are passing through the wire collide with the metal atoms of the wire. The more you increase the length of the wire, the more collisions there will be between the metal atoms and electrons. ...read more.


In this case I can carry out my experiment without having to worry about anything going wrong and it also allows my results to be more accurate. Equipment: * Ammeter * Voltmeter * Low Voltage Power Supply * Variable Resistor * Connecting Wires & Crocodile Clips * Wires Of Nichrome 32 (all the same diameter) Method: 1. Set up a circuit as shown in the diagram above. 2. Measure a 100cm length of Nichrome 32 wire and connect it to the circuit. 3. Set power supply to 6 volts DC and turn on. 4. Record the current and voltage and quickly turn off the power supply. 5. Between each reading, allow the wire to cool and change the variable resistor. 6. Repeat steps 3 - 5 two more times. 7. Change length of wire to 90cm, and repeat steps 3 - 6. ...read more.


10 0.94 1.02 0.92 20 1.08 0.90 1.20 30 1.54 0.74 2.08 40 1.98 0.65 3.04 50 2.50 0.60 4.16 60 2.96 0.58 5.10 70 2.90 0.46 6.30 80 3.19 0.44 7.25 90 3.61 0.45 8.02 100 3.52 0.37 9.51 Average Resistance: Length (cm) Average Resistance (ohms) 10 0.80 + 0.83 + 0.92 � 3 = 1.93 20 1.27 + 1.18 + 1.20 � 3 = 2.85 30 1.96 + 2.08 + 2.08 � 3 = 4.73 40 3.52 + 3.18 + 3.04 � 3 = 7.71 50 4.17 + 4.13 + 4.16 � 3 = 9.68 60 4.98 + 4.16 + 5.10 � 3 = 10.84 70 6.33 + 6.37 + 6.30 � 3 = 14.80 80 7.45 + 7.37 + 7.25 � 3 = 17.23 90 8.52 + 8.51 + 8.02 � 3 = 19.70 100 9.46 + 9.50 + 9.51 � 3 = 22.13 ?? ?? ?? ?? ...read more.

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Response to the question

Response to the question is done well. The candidate misses certain parts out which has affected how well we can assess this essay but from the depth of scientific consideration present and the presentation of the essay and results ...

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Response to the question

Response to the question is done well. The candidate misses certain parts out which has affected how well we can assess this essay but from the depth of scientific consideration present and the presentation of the essay and results the candidate has performed the response to the experiment to a high standard.

Level of analysis

The introduction and fair test section are well constructed. They set out what the candidate is going to do concisely and clearly and the candidate explains why certain factors are kept the same effectively and how they are going to do this with good scientific terms. The prediction is explained well and is backed up with well explained scientific theory. The evaluation, conclusion and fair test sections are missing. The candidate carries out preliminary work which is good to give the candidate an idea of what the results should be like and make adjustments if anything other than what the candidate has considered affects the experiment. Graphs are well presented. Decimal places used in the table are consistent which is needed for accurate evaluations.

Quality of writing

The presentation of the essay is professional with a nicely done title page and clear text. The subheadings and paragraphing is also to a good standard with the essay following a clear route. The method and equipment are well organised in a bullet point form with a diagram to back it up. Punctuation, grammar and spelling are all to a high level.

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