• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

It this experiment the aim is to make sense of the data that I collect from my experiment using the relevant formulas.

Extracts from this document...

Introduction

Katy Morris                Physics Coursework        41240        1714

It this experiment the aim is to make sense of the data that I collect from my experiment using the relevant formulas.

The experiment is rolling a steel ball of weight of 28.09g down a ramp.  I will roll the ball at different heights.

Once I have collected my results I will analysis my data using the relevant formulas and graphs.

The following formulas I could use in the analysis of my data

image00.png        Speed = Distances / Time

image00.png        Force = Mass x Acceleration        

image00.png        Pythagoras

image00.png        Kinetic energy = ½ x mass x speed²

image00.png        Potential energy

image00.png        Trigonometry

Also I could use the following kinetic equations

image00.png        S=UT + ½AT²

image00.png        V² = U² + 2AS

image00.png        V = U + AT

image00.png        A = (V – U)/T

As you can see from the diagram the ramp will me placed against a table at a height of 0.92M and the maximum length that the ball can be rolled is 244cm as that is the length of the slope.image01.png

Things that could affect the ball are:

  • Air resistance on the ball as it goes down the hill
  • Friction on the ball at the point where it touches the ramp
...read more.

Middle

Time  B (seconds)

Time C (seconds)

Average time (seconds)

A

B

C

A + b + c / 3

0.2

0.38

0.25

0.25

0.21

0.4

0.47

0.4

0.41

0.29

0.6

0.53

0.56

0.47

0.363333

0.8

0.69

0.65

0.65

0.446667

1

0.78

0.89

0.72

0.556667

1.2

0.96

0.85

0.84

0.603333

1.4

0.97

0.9

1.1

0.623333

1.6

0.91

1

1.03

0.636667

1.8

1.12

1.09

1.09

0.736667

2

1.15

1.15

1.13

0.766667


image03.png


The graph that my results produced wasn’t what I was expecting. After a while they results become a bit hard to predict what the next result will me.  From the results that I collect I hope to calculate:

  1. The speed of the ball,
  2. Its acceleration,
  3. Power,
  4. Velocity,
  5. Kinetic and potential energy.
  1. The speed of the ball:

If we take our table and add the speed column:

Speed = distance x time

Eg.        0.2m x 0.29 = 0.06

...read more.

Conclusion

image00.png        The surface, which the ball was rolled down, could have been uneven and as the ball was rolled at different places this could have had an effect.

GRAPHS

  1. This graph is a distance time graph- the graph was a smooth curve.  When I added a line of best fit the points were all close to the line.  Time is proportional to the distance that the ball has travelled.
  2. Graph 2 Shows force over acceleration.  To have acceleration you need a big force.
  3. Graph 3 had a funny middle in it with a hump.  I added a straight line but it still didn’t look right.  I am not sure why this happened.
  4. The distance over acceleration graph produced a straight line as you would expect as distance is proportional to the acceleration to the ball
  5. Speed against distance graph produced a smooth curve.
  6. Velocity against time started as a smooth curve but in the middle the velocity went up and then smoothed out.  The higher the ball the greater the velocity
  7. Distance against potential energy, the higher the ball the greater potential energy it has.

...read more.

This student written piece of work is one of many that can be found in our GCSE Forces and Motion section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related GCSE Forces and Motion essays

  1. Bouncing Ball Experiment

    Therefore the energy that the ball hits the floor with = mh1g * The proportion of energy lost when ball hits the floor = The Coefficient to the restitution of the two objects (CR) * Energy ball leaves the floor with = CR (mh1g)

  2. Trolly Experiment

    Now that I have acceleration for the trolley I can model it going down a slope and find out the model acceleration. This value can then be subtracted from the actual value to give resistance to the path of the trolley.

  1. Investigate and measure the speed of a ball rolling down a ramp.

    2 As the Gravitational potential energy increases, the kinetic energy also increases proportionally 3 As the height of the ramp increases the G.P.E also increases proportionally 4 As the speed of the ball (squared) increases the kinetic energy exerted is also increased proportionally.

  2. Squash Ball and Temperature Investigation

    With this increase of air pressure within the ball, the ball will deform less when it comes into contact with the floor than it would when it has a lower air pressure because constant, rapid collisions of the air molecules inside the ball help maintain the shape of the ball better at this higher pressure.

  1. In this experiment I aim to find out how the force and mass affect ...

    As the metal ball rolls over them, it completes the circuit and starts the stop-clock. As it then rolls over the second set, it again completes the circuit and stops the clock. I will take three readings, and in the end take the average.

  2. Investigating the amazingness of theBouncing Ball!

    The total kinetic energy, however, usually decreasing , since the impact converts some of the kinetic energy to heat and/or sound and /or permanently distorts the bodies; leaving them with a decreased amount of potential energy. For the collision to be elastic the kinetic energy isn't lost but merely converted

  1. Making Sense of Data.

    velocity at the start of the ramp than at the end, which can be seen due to the fact that the gradient becomes shallower. This must mean that there is a larger force opposing the trolley as it picks up speed and could be due to air resistance.

  2. Experimental Techniques; Analysis of Boundary Layer Data.

    80 0.08 1.5508 0.0515 2.450695582 14.4531533 0.018608435 90 0.09 1.5506 0.0383 2.44780599 14.4427672 0.01382895 100 0.1 1.5506 0.0382 2.44780599 14.4427672 0.013792843 From such data the boundary layer integral parameters can be determined using: Displacement thickness, Momentum Thickness , Shape Factor, The boundary layer thickness has been approximated here using the definition provided by F.M White.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work