My aim is to investigate what effect differing concentrations of sucrose solutions have on Osmosis in raw potato chips.

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AIM

My aim is to investigate what effect differing concentrations of sucrose solutions have on Osmosis in raw potato chips.

This investigation is to determine how the mass of a raw potato chip is affected, by being immersed in different concentrations of a sucrose in water solution, due to the process of Osmosis.

Prediction

Osmosis is defined as ‘the movement of water molecules from an area of high water concentration to an area of low water concentration, across a semi-permeable membrane’ (Collins, 1999)

My prediction is that in a high concentration of water the amount of solute (e.g. sucrose) is low. This could be called a weak or dilute solution. In a low concentration of water the amount of solute (e.g. sucrose) is high. This could be called a strong or concentrated solution.

I predict that when two such solutions are divided by a semi-permeable membrane the water molecules will move from the area of high concentration to the area of low concentration, until both sides of the membrane are of equal osmotic pressure i.e. isotonic.          

This can be seen in living cells. The cell membrane in cells is semi-permeable and the vacuole contains a sugar solution. So, when a cell is placed in distilled water, water molecules will move across the semi-permeable into the cell by Osmosis, making the cell swell. This cell is now referred to as turgid. If done with potato cells, the cells would increase in length, volume and mass because of the extra water now contained in them.  

If these potato cells were placed in a solution with a low water concentration, then the opposite would happen. Water molecules would move out of the cell into the solution. In extreme cases the cell membrane breaks away from the cell wall and the cell is referred to as Plasmolysed. The potato cells will have decreased in length, volume and mass.

The greater the concentration of water in the external solution the greater the amount of water that enters the cell by the process of Osmosis. The smaller the concentration of water in the external solution the greater the amount of water that leaves the cell.

However there will be a point where the osmotic pressure of the water molecules inside and outside the potato cells is equal (isotonic). At this point there should be no change in the length, volume and mass of the potato, as the net movement of water should be zero, as no osmosis has occurred.

Using this information a graph and prediction can be made.

At point A the graph suggests that no Osmosis has occurred, suggesting that the concentration of water inside the cell is equal to the solution outside.

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At point B (high water concentration), there is no indication that the cell is increasing further in size. This is because the cell is fully turgid and no more water can enter.

At point C (low water concentration), there is no indication that the cell is decreasing further in size. This is because the cell is fully plasmolysed and no more water can leave the cell.

Plan

  • I intend to fully immerse 3 cm lengths, with a diameter of    1 cm², of raw potato chips in 15cm³ of sucrose ...

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